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brilliants [131]
4 years ago
12

The strength of intermolecular forces between particles affects physical properties of substances such as boiling point, melting

point, surface tension, and vapor pressure. Which substance has the highest melting point
A) C2H5O

B) C2H6

C) H2O

D) C6H6
Physics
2 answers:
Alexxx [7]4 years ago
7 0

Answer:

D) C6H6

Explanation:

The strength of intermolecular forces between particles affects physical properties of substances such as boiling point, melting point, surface tension, and vapor pressure. Which substance has the highest melting point

A) C2H5O

B) C2H6

C) H2O

D) C6H6

C2H5O has a melting point of -114.1^{0}c

C2H6  has a melting point of -182.8^{0}c

H2O has a melting point of 0^{0}c

c6h6 has a melting point of 5^{0}c

benzene as the highest melting point

When molecules are tightly packed together, a substance has a higher melting point than a substance with molecules that do not pack well. ... Molecular mass also affects the melting point. , smaller molecules melt at lower temperatures than larger molecules.

melting point is the temperature at which a substance coexist as both solid and liquid without any noticeable change in temperature

lara [203]4 years ago
5 0
The right answer is h2o


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A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr
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Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is  \phi _2  = 1.57 \  rad

Explanation:

From the question we are told that

    The wavelength of the spherical wave is  \lambda =  2.0 \ mm =  \frac{2}{1000} = 0.002 \ m

    The first radius  is  r_1  = 4.0 \ mm  = \frac{4}{1000}  = 0.004 \ m

     The phase at that instant is  \phi _1 = \pi \ rad

     The second radius is  r_2  = 3.5 \ mm  = \frac{3.5}{1000}  = 0.0035 \ m

Generally the phase difference is mathematically represented as

          \Delta  \phi =  \phi _2 -  \phi _1

this can also be expressed as

         \Delta \phi =  \frac{2 \pi }{\lambda } (r_2 - r_1 )

So we have that

   \phi _2 -  \phi _1 =   \frac{2 \pi }{\lambda } (r_2 - r_1 )

substituting values

     \phi _2 -  \pi =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )

    \phi _2  =   \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) +   3.142

   \phi _2  = 1.57 \  rad

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A coil consisting of 50 turns of wire is powered by a 9V battery. If the coil draws 1.5 A from the battery, what is the MMF, in
aivan3 [116]

A. 75 ampere-turns

<u>Explanation:</u>

Given:

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