I have no idea I need the answer too
Answer:
206.8965517 n
Explanation:
First, we need to see that 60:29 is 2.078965517:1. Then we need to multiply the energy put 29 cm from the fulcrum by 2.078965517, giving us the end result of our answer.
When you talk about Hooke's law, it always have to do something with springs. Hooke's Law, from Robert Hooke, saw a relation between the force applied to the spring and the extension of its length. The equation is: F = kx, where k is the spring constant and x is the displacement of the original and stretched lengths. In other words, x is the length of deformation. Hence, the object must be elastic to come up with a displacement or deformation, in the first place. Then, the Hooke's Law is only applicable to elastic materials.
I think it’s C. But I’m not completely sure.
Answer: a) 0.315 (V/L)
Explanation:
From Conservation of angular momentum, we know that
L1 = L2 ,
Therefore MV L/2 = ( Irod + Ib) x W
M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W
M/8 X VL = (ML^2/16 + ML^2 /3 )
After elimination we have,
V/8 = 19/48 x L x W
W = 48/8 x V/19L = 6/19 x V/L
Therefore W = (0.136)X V/L
