Let x be the width of the cardboard (which means the length of the cardboard is x+88), then the dimensions of the box are:
Length = [(x + 88) - 2(33)]
Width = x - 2(33)
Heighth = 33
Volume = length · width · heighth
144,144 = [(x + 88) - 2(33)] · [x - 2(33)] · 33
144,144 = (x+22)(x-66)(33)
4368 = (x+22)(x-66)
4368 = x² - 44x - 1452
0 = x² - 44x - 5820
use the quadratic formula to calculate that x = 101
Answer: cardboard width = 101, cardboard length = 189
Given the function:

Let's find the amplitude and period of the function.
Apply the general cosine function:

Where A is the amplitude.
Comparing both functions, we have:
A = 1
b = 4
Hence, we have:
Amplitude, A = 1
To find the period, we have:

Therefore, the period is = π/2
The graph of the function is shown below:
The parent function of the given function is:

Let's describe the transformation..
Apply the transformation rules for function.
We have:
The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.
ANSWER:
Amplitude = 1
Period = π/2
Transformation = horizontal compression.
Answer: 110 -10x
Step-by-step explanation:
You do pemdas
So 11•10 = 110
Then -10•x = -10x
And then you get
110-10x
A radioactive atmosphere around the area and an expensive, hard time cleaning everything up.
Your answer would be 15 m if i’m doing it right