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Tasya [4]
3 years ago
7

Consider what happens at the moment when the block leaves the surface of the globe. Which of the following statements are correc

t?
- The net acceleration of the block is directed straight down.
- The component of the force of gravity toward the center of the globe is equal to the magnitude of the normal force.
- The force of gravity is the only force acting on the block.
Physics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

Option (3) is correct.

Explanation:

when the block leaves the surface, the normal reaction acting on the block is zero and the acceleration is acceleration due to gravity which acts towards the centre of globe.

So, only the force of gravity acts on the block which acts towrads the centre of the globe.

Option (3) is correct.

erma4kov [3.2K]3 years ago
6 0

Answer:

Statement 1 and 3 are correct.

Explanation:

1. The mass moves  downward, so the net acceleration of the block is straight downward.

2.The mass is sliding through the globe, so only the force of gravity is acting on the mass which pulls it in downward direction. The force of gravity has two components [mg sin∅] and [mg cos∅].

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Which factor listed below most likely results in the loss of genetic variation from small populations?
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3 years ago
PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
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22. a - (vf^2 - vi^2)/(2d) 
a = (0 - 23^2)/(170) 
a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
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t = 11 sec to reach 33 m/s^2
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24. The sprinter starts from rest. The average acceleration is found from: 
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25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
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I hope this helps!! 

5 0
3 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
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d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
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2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
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