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soldi70 [24.7K]
2 years ago
11

In the visible spectrum, red light has the lowest frequency and violet light has the highest. List the following colors in order

of increasing energy. green blue yellow orange A) blue, green, yellow, orange B) orange, yellow, green, blue C) yellow, orange, blue, green D) green, blue, orange,w
Physics
2 answers:
dalvyx [7]2 years ago
6 0
The correct answer is:
<span>B) orange, yellow, green, blue 

the energy of the photons of light is directly proportional to the frequency of the light. This means that the lower the frequency, the lower the energy, and the higher the frequency, the greater the energy. 

Therefore, the order in increasing energy  is exactly the same as the order in increasing frequency, which is:
</span><span>
orange, yellow, green, blue </span>
LenaWriter [7]2 years ago
6 0

The answer is b !!!!!!

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I think it is the Federal Pell Grant Program.

Explanation:

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Read 2 more answers
A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

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\phi=\cos^{-1}(0.6)

\phi=53.13^{\circ}

Put the value of Φ in equation (I)

Q=600\tan(53.13)

Q=799.99\ kVAR

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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003 (part 1 of 2) 10.0 points
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