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mylen [45]
3 years ago
15

Question#7:a) A television uses 1500J of electric energy to produce 1100J 1 point

Physics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

a.73.3%

b.26.6%

Explanation:

a. The efficiency is the energy output, divided by the energy input, and expressed as a percentage.

#Given the energy input as 1500J and the subsequent output as 1100J, the TV's efficiency is calculated as:

<em />\eta=\frac{E_o}{E_i}\\\\=\frac{1100}{1500}\times 100\%\\\\=73.33\%<em />

Hence, the TV has an efficiency of 33.3%

b. From a above, we know that the TV has an output of 1100J and input of 1500J.

-We therefore calculate it's wastage as the difference between output and input:

<em>Wastage=Energy Input-Energy Output=1500J-1400J=400J</em>

<em />E_w=\frac{E_{wasted}}{E_i}\times 100\%\\\\=(400/1500)\times100\%\\\\=26.67\%<em />

Hence, the TV has wasted of 26.6%

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