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3 years ago

Question#7:a) A television uses 1500J of electric energy to produce 1100J 1 point

Physics

1 answer:

Vesnalui [34]3 years ago

4 0

Answer:

a.73.3%

b.26.6%

Explanation:

a. The efficiency is the energy output, divided by the energy input, and expressed as a percentage.

#Given the energy input as 1500J and the subsequent output as 1100J, the TV's efficiency is calculated as:

<em /> $\eta=\frac{E_o}{E_i}\\\\=\frac{1100}{1500}\times 100\%\\\\=73.33\%$ <em />

Hence, the TV has an efficiency of 33.3%

b. From a above, we know that the TV has an output of 1100J and input of 1500J.

-We therefore calculate it's wastage as the difference between output and input:

<em>Wastage=Energy Input-Energy Output=1500J-1400J=400J</em>

<em /> $E_w=\frac{E_{wasted}}{E_i}\times 100\%\\\\=(400/1500)\times100\%\\\\=26.67\%$ <em />

Hence, the TV has wasted of 26.6%

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<h3>De Broglie wavelength:</h3>

The wavelength that is incorporated with the moving object and it has the relation with the momentum of that object and mass of that object. It is inversely proportional to the momentum of that moving object.

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Learn more about de Broglie wavelength on

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