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Eduardwww [97]
2 years ago
10

When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and

viewer. Unlike other forms of social video, you’ll get more views and engagement if your video ________.a. is longer and repeats key points.b. is full of interesting transitions and editing techniques.c. uses unusual lighting and sound effects.d. includes a pdf attachment with details from the broadcast.e. is short and action packed.
Physics
1 answer:
Andru [333]2 years ago
6 0

Answer:

When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and viewer. Unlike other forms of social video, you’ll get more views and engagement if your video

is longer and repeats key points.

Explanation:

When broadcasting live on social media, one should be live for long because in this way one can get more views as audience will increase with time. There should be an interaction with the audience like answering their questions which they write in the comments section. These comments and views will make this video to the top of news feed. Secondly the most important thing is the content of the video. One must focus on the information or knowledge he/she wants to convey and must repeat the key points again and again so that one who has missed the important points will be able catch them later.

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What are input energy and output energy?​
makkiz [27]

Answer:

Explanation:

Input​ refers to the amount of energy put into a device, and ​ output​ refers to the amount of energy that comes out. A device may change the type of energy but not the amount. For example, a light bulb's input energy is the form of electrical energy, and its output energy is in the form of light and heat. Efficiency.

3 0
2 years ago
A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees to the right of her orig
r-ruslan [8.4K]

Answer:

2406 miles

Explanation:

Let A be the starting position, B the junction position and C the final position after flying the 3.5 hrs. Also, let b be the distance from the starting point:

\angle ABC =(180-10) \textdegree=170\textdegree

#Distance traveled in 1.5hrs is;

c=690x1.5\\=1035mi

#Distance traveled in next two hrs:

a=690\times 2\\=1380mi

#Now using the Cosine Rule:

b^2=a^2+c^2-2ab\cos B\\\\=1380^2+1035^2-2(1380)(1035)cos170\textdegree\\\\b^2=5788.83\\\\b\approx 2406.00 \ mi

Hence, the pilot is 2406 miles from her starting position.

4 0
3 years ago
What is one disadvantage of using a ramp?
11111nata11111 [884]
Answer: a disadvantage of using a ramp is that it is not safe
4 0
2 years ago
Consider the two-body situation at the right. A 300kg crate rests on an inclined plane and is connected by a cable to a 100 kg m
trasher [3.6K]

Answer:

a= 0.578 m/s

T = 1037.8 N

Explanation:

Data

m₁= 300 kg

m₂= 100 kg

inclined plane, θ =  30°

μk = 0.120

Newton's second law to m₁:

We define the x-axis in the direction parallel to the movement of the 300kg (m₁) crate on the ramp and the y-axis in the direction perpendicular to it.

∑F = m₁*a Formula (1)

Forces acting on m₁

W₁: m₁ weight : In vertical direction

N : Normal force : perpendicular to the inclined plane

f : Friction force: parallel to the inclined plane

T:  cable tension : parallel to inclined plane

Calculated of the W₁

W₁=m₁*g

W₁= 300kg* 9.8 m/s² = 2940 N

x-y weight components

W₁x= W₁sin θ =2940 N*sin(30)° =1470 N

W₁y= W₁cos θ =2940 N *cos(30)° =2156.4 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay    ay = 0

N - W₁y = 0

N = W₁y

N = 2156.4 N

Calculated of the f

f = μk* N= (0.120)*(2156.4 N)

f = 258.77 N

Newton's second law to m₁ in direction  x-axis :

∑Fx = m₁*ax   ,ax  =a

We assume that m₁ descends on the inclined plane and we positively take the direction of movement:

wx-f-T = m*a

wx - f - m*a =T

1470  -258.77 -300*a =T

T= 1211.23-300*a   Equation (1)

Newton's second law to m₂

∑Fy = m₂*ay   ,ay  =a

Forces acting on m₂

W₂: m₂ weight : In vertical direction

T:  cable tension:In vertical direction

Calculated of the W₂

W₂=m₂*g

W₂= 100kg* 9.8 m/s² = 980 N

∑Fy = m₂*a

Because we assume that m₁ descends on the inclined plane, then, m₂ ascends  vertically, we take positive the direction of movement:

T-W₂ = m₂*a

T-980 = 100*a

T = 980 + 100*a Equation (2)

Problem development

Equation (1) =  Equation (2) = T

1211.23-300*a= 980  + 100*a

1211.23- 980 = 100*a + 300*a

231.23 = 400*a

a= 231.23 / 400

a= 0.578 m/s

Because the acceleration tested positive then effectively m₁ descends on the inclined plane and m₂ ascends  vertically.

We replace a= 0.578 m/s in the equatión (2)

T = 980 + 100* (0.578 )

T = 1037.8 N

5 0
3 years ago
Scientific theories are deductive in nature.?
dolphi86 [110]

Answer:

deductive reasoning usually follows steps .

  • That is, how we predict what the observations should be if the theory were correct

8 0
2 years ago
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