Answer: 40.650406504065 or 40 minutes and 39 seconds.
Explanation:
1 k = 1000m
race = 10000m
runner time = 10000 / 4.1
runner time = 2439.0243902439024 seconds
runner time = 2439.0243902439024/60 = 40.650406504065 or 40 minutes and 39 seconds.
Volume = mass/density
Volume = 15000 g/45 g/cm3 ≈ 333.3 cm<span>3</span>
<span>We can use an equation to find the gravitational force exerted on the HST.
F = GMm / r^2
G is the gravitational constant
M is the mass of the Earth
m is the mass of the HST
r is the distance to the center of the Earth
This force F provides the centripetal force for the HST to move in a circle. The equation we use for circular motion is:
F = mv^2 / r
m is the mass of the HST
v is the tangential speed
r is the distance to the center of the Earth
Now we can equate these two equations to find v.
mv^2 / r = GMm / r^2
v^2 = GM / r
v = sqrt{GM / r }
v = sqrt{(6.67 x 10^{-11})(5.97 x 10^{24}) / 6,949,000 m}
v = 7570 m/s which is equal to 7.570 km/s
HST's tangential speed is 7570 m/s or 7.570 km/s</span>
The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:
- The distance to go between airports A and C is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.
In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C
Let's use the Pythagoras theorem to find the distance traveled
R = Ra x² + y²
R = 10³
R = 373.6 10³ m
They indicate the average speed for which we can use the uniform motion ratio
v = 
t = 
They ask for the time in in from airport A to B, we calculate
t = 360 10 ^ 3/170
t = 2.117 10³ s
In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:
- The distance to go between airports A and C B is 373.6 10³ m
- The time to go from airport A to B is 2117 s
Learn more here: brainly.com/question/15074838