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Eduardwww [97]
3 years ago
10

When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and

viewer. Unlike other forms of social video, you’ll get more views and engagement if your video ________.a. is longer and repeats key points.b. is full of interesting transitions and editing techniques.c. uses unusual lighting and sound effects.d. includes a pdf attachment with details from the broadcast.e. is short and action packed.
Physics
1 answer:
Andru [333]3 years ago
6 0

Answer:

When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and viewer. Unlike other forms of social video, you’ll get more views and engagement if your video

is longer and repeats key points.

Explanation:

When broadcasting live on social media, one should be live for long because in this way one can get more views as audience will increase with time. There should be an interaction with the audience like answering their questions which they write in the comments section. These comments and views will make this video to the top of news feed. Secondly the most important thing is the content of the video. One must focus on the information or knowledge he/she wants to convey and must repeat the key points again and again so that one who has missed the important points will be able catch them later.

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A certain runner averages 4.1 m/s over a 10
Ghella [55]

Answer: 40.650406504065 or 40 minutes and 39 seconds.

Explanation:

1 k = 1000m

race = 10000m

runner time = 10000 / 4.1

runner time = 2439.0243902439024 seconds

runner time = 2439.0243902439024/60 = 40.650406504065 or 40 minutes and 39 seconds.

6 0
3 years ago
A bag of sand has a density of 45 g/cm3 and a mass of 15 kg. How much space does the sand take up?
Aleks [24]

Volume = mass/density

 

Volume = 15000 g/45 g/cm3 ≈ 333.3 cm<span>3</span>

3 0
3 years ago
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The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. Given that Earth’s mass is 5.97 × 1024 kg and its radius i
Sergio039 [100]
<span>We can use an equation to find the gravitational force exerted on the HST. F = GMm / r^2 G is the gravitational constant M is the mass of the Earth m is the mass of the HST r is the distance to the center of the Earth This force F provides the centripetal force for the HST to move in a circle. The equation we use for circular motion is: F = mv^2 / r m is the mass of the HST v is the tangential speed r is the distance to the center of the Earth Now we can equate these two equations to find v. mv^2 / r = GMm / r^2 v^2 = GM / r v = sqrt{GM / r } v = sqrt{(6.67 x 10^{-11})(5.97 x 10^{24}) / 6,949,000 m} v = 7570 m/s which is equal to 7.570 km/s HST's tangential speed is 7570 m/s or 7.570 km/s</span>
6 0
3 years ago
Read 2 more answers
(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a
GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

  • The distance to go between airports A and C  is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

               R = Ra x² + y²

               R =   10³

               R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

               v = \frac{\Delta y }{t}

                t = \frac{\Delta y}{v}

They ask for the time in in from airport A to B, we calculate

                t = 360 10 ^ 3/170

                t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

  • The distance to go between airports A and C B is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

5 0
3 years ago
Hurry please I don’t have long for this for a test !!!
Anna35 [415]
I think the Answer is b
7 0
3 years ago
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