D. There is a known constant concentration of C14 in Nature. As we consume living things to survive our bodies (made of carbon) stop replenishing our body's carbon (we stop eating) and start to decay. Since we know the 1/2 life of C14 and the ratio of C14 to normal C12 we can determine fairly accurately how long ago a thing stopped consuming carbon (e.g. when it died)
Answer:
B
Explanation:
Both low and high mass stars begin as nebulae, then become protostars. Both use nuclear fusion to form hydrogen in the main sequence.
The differences are that low mass stars have longer life cycles and become white dwarfs. High mass stars have shorter life cycles and undergo supernova explosions.
Using the formula for bodies in projectile
motion, we can calculate for the velocity v:
d = (v^2) * (sin2theta) / g
Substituting the given values:
193 m = (v^2) * (sin(2*44.4)) / (9.8 m/s^2)
v= 50.5 m/s
Calculating for the impulse I,
I = mf * vf – mi * vi
since mf = mi and vi = 0 (the golf ball starts
form rest)
I = m * vf
I = 0.046 kg * 50.5
m/s
I = 2.323 kg m/s
Calculating for the force of impact:
I = F t
<span>F = (2.323
kg m/s) / (6.92 x 10^-3 s)
</span>
<span>F =335.7 kg m/s^2 = 335.7 N</span>
The correct answer to the question is 8.33 minutes.
CALCULATION:
The distance of earth from sun s = 150 million km.
We know one million = 10 lakh = 
Also 1 km = 
Hence, the distance s = 
= 
The speed of light c = 300,000 km per second
= 
We are asked to calculate the time.
The time of the reaching earth is calculated as -




We know one minute = 60 second.
Hence, 500 seconds = 
=
[ans]