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Levart [38]
2 years ago
7

How much force is needed to lift a 25 kg mass at a constant velocity?

Physics
1 answer:
marta [7]2 years ago
5 0

F = 245N

The Acceleration of an object in a free fall is 9.8 m/s

force= 25kg X 9.8m/s

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Imagine that the light you observe from space is exhibiting a redshift. This would mean that the Universe is Choose one: A. trav
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Answer: C. Expanding

Explanation:

When an object moves away from an observer, the light waves emitted by the object are stretched out making them have move towards the red end of the electromagnetic spectrum, where light has a longer wavelength. This phenomenon is known as the redshift (cosmological redshift). For most astronomical objects, the observed spectral lines are all shifted to longer wavelengths. It is caused solely by the expansion of the Universe and thus, the value of a redshift indicates the recession velocity of the expanding object, or its distance.

Redshift is opposed to the blueshift. Blue light wavelengths tend to be closer together hence blueshift light tends to be emitted from objects that are collapsing.

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3 years ago
List some benefits of Cardiovascular exercise:
lozanna [386]

Answer:

Aerobic exercise reduces the risk of many conditions, including obesity, heart disease, high blood pressure, type 2 diabetes, metabolic syndrome, stroke and certain types of cancer. Weight-bearing aerobic exercises, such as walking, help decrease the risk of osteoporosis.

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2 years ago
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the average power of the Sun is 3.79x1026 Watts, answer the following questions: 13. What is the average intensity of light at E
Lemur [1.5K]

Explanation:

Given that,

Average power of sun P=3.79\times10^{26}\ Watt

We need to calculate the intensity of light at Earth's position

Using formula of intensity

I=\dfrac{P_{avg}}{4\pi r^2}

Where, I = intensity

P = power

Put the value into the formula

I=\dfrac{3.79\times10^{26}}{4\pi\times(1.496\times10^{11})^2}

I=1347.616\ W/m^2

So, The intensity is 1347.616 W/m².

(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully reflective

P = \dfrac{2I}{c}

Put the value into the formula

P=\dfrac{2\times1347.616}{3\times10^{8}}

P=8.984\times10^{-6}\ N/m

(B).  We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully absorptive

P=\dfrac{I}{c}

P=\dfrac{1347.616}{3\times10^{8}}

P=4.492\times10^{-6}\ N/m

Hence, This is the required solution.

6 0
3 years ago
What are the uses of a magnet?
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Answer:

A magnet is used in a compass to show the direction.

Magnets are used in medical equipment.

Powerful magnets are used to lift objects

they are used in refrigerator, televisions, earphones etc

5 0
2 years ago
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Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0
3 years ago
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