Answer:
λ = 2042 nm
Explanation:
given data
screen distance d = 11 m
spot s = 4.5 cm = 4.5 × m
separation L = 0.5 mm = 0.5 × m
to find out
what is λ
solution
we will find first angle between first max and central bright
that is tan θ = s/d
tan θ = 4.5 × / 11
θ = 0.234
and we know diffraction grating for max
L sinθ = mλ
here we know m = 1 so put all value and find λ
L sinθ = mλ
0.5 × sin(0.234) = 1 λ
λ = 2042.02 × m
λ = 2042 nm
Explanation:
The answer is in the pic above
Answer:
The mailbag will take 2.44 seconds to reach the ground.
Explanation:
The height of a helicopter above the ground is given by:
Height of helicopter at t = 2.10 seconds
The helicopter releases a small mailbag from the height of 29.17 m.
The initial velocity of mailbag = u = 0 m/s
Duration in which mailbag will reach the ground = T
Acceleration due to gravity = g =
Using second equation of motion ;
We have , s = 29.17
u = 0 m/s
t = T
Solving for T, we gte :
T = 2.44 seconds
The mailbag will take 2.44 seconds to reach the ground.
Answer:
Explanation:
When the ball is at the bottom position of the vertical circle, the forces acting on the ball are:
- The tension in the string, , upward
- The weight of the ball, , downward
The resultant of these forces must be equal to the centripetal force, which points upward as well (towards the center of the circle), so:
(1)
where is the speed of the ball at the bottom of the circle, r the radius of the circle, and m the mass of the ball.
When the ball is at the top position of the vertical circle, the weight still acts downward, however the tension in the string also acts downward, so the equation of the forces becomes:
(2)
where
is the tension in the string in the top position
is the speed of the ball in the top position
By subtracting eq.(2) from eq.(1), we find:
So, this is the difference in tension between the two positions.