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zaharov [31]
4 years ago
8

2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i

s 0.92 probability that the calculator will work on any given day. Because the final exam is so important, she plans to use redundancy by bringing in two TI-84 Plus calculators. What is the probability that she will be able to complete her exam with a working calculator? Does she really gain much by bringing in the backup calculator? Explain. [6 points]
Mathematics
1 answer:
Anarel [89]4 years ago
7 0

Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

_____

My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)

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Nitella [24]

Answer:

f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\

Step-by-step explanation:

The functions are given f and g using coordinates.

Whenever we will ask for f(a), we look for "a" in the x coordinate of the function f and find the corresponding value. THAT IS THE ANSWER.

If we ask for g(b), we look for "b" in the x coordinate of the function g and find the corresponding value. THAT IS THE ANSWER.

So,

f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\

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4 years ago
I need the answer for this question
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7 0
3 years ago
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You have made two of the exact same necklaces that cost you a total of $15 in supplies. You have chosen to mark up the price by
tatyana61 [14]

Answer:

A) The selling price for each necklaces is $8.625

B) The profit mark in each necklaces is 15%

Step-by-step explanation:

Given as :

The total cost of two necklaces = c.p = $15

The markup percentage for the necklaces = m = 15%

Let The selling price for both necklaces = s.p

A ) <u>Now, From markup method</u>

m% = \dfrac{s.p - c.p}{c.p}

or, 15% =  \dfrac{s.p - 15}{15}

or, 15% =  \dfrac{s.p}{15} - 1

or, \dfrac{s.p}{15} = 1 + 15%

or, \dfrac{s.p}{15} = 1 +  \dfrac{15}{100}

or, \dfrac{s.p}{15} =  \dfrac{100 + 15}{100}

or,  \dfrac{s.p}{15} =  \dfrac{115}{100}

∴ s.p = \frac{15\times 115}{100}

I.e s.p = $17.25

So, selling price of two necklaces = s.p = $17.25

or, selling price of one necklaces = s.p = \dfrac{17.25}{2} = $8.625

Hence, The selling price for each necklaces is $8.625

<u>Now, Again</u>

B) ∵ The total cost of two necklaces = c.p = $15

So, The cost price of one necklaces = \dfrac{15}{2} = $7.5

∴ profit% for each necklace =  \dfrac{s.p - c.p}{c.p}

i.e profit% for each necklace =  \dfrac{8.625 - 7.5}{7.5}

Or, profit% for each necklace =  \dfrac{1.125}{7.5}

Or, profit% for each necklace = 0.15

So, The profit make in each necklaces = 15%

Hence, The profit mark in each necklaces is 15%

Answer

8 0
3 years ago
Solve the following problem. Round answer to two decimal places when necessary.
MrMuchimi

Answer:

D = 11

Step-by-step explanation:

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D = 4 + (2 * 9) - 11

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Nadusha1986 [10]

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