The total number of 3 digit even numbers is 450
Step-by-step explanation:
Step 1 :
We need to determine the number of 3 digit numbers which is even and the leftmost digit is not zero .
The 3 digits with left most digit not equal to zero starts from 100 and goes up to 998
If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.
Step 2:
The last number l in this series is 998 .
So we have
a = 100
l = 998
d = 2
The nth term in the arithmetic progression is given by a + (n-1) d
so substituting the above values we get
100 + (n-1) 2 = 998
2n = 900 => n = 450
Step 3 :
Answer :
The total number of 3 digit even numbers is 450
Answer:
Step-by-step explanation:
<u>The difference in balances is:</u>
- 5000*(1 + 0.04)^3 - 5000*(1 + 0.04*3) =
- 5624.32 - 5600 =
- 24.32
Answer:
8
Step-by-step explanation:
Answer:
2^4
2 * 2 * 2 * 2
Step-by-step explanation:
In the question above :
Write an exponential expression:
Base = number between 0 and 10
Exponent = number different from the base between 0 and 10
Let base = 2
Let exponent = 4
Hence, exponential expression will be
Base^exponent
2^4 (standard form)
Expanded form:
2 * 2 * 2 * 2 (multiply 2 in 4 places)
