Answer:
C
Step-by-step explanation:
A = r^2 h/3
A= 235.62
B = r^2 h
B = 235.62
They are equal
The half-life is 29 years.
116 : 29 = 4
So we will have 4 periods of half-life:
( 1/2 )^4 = 1/16
150 g * 1/16 = 9.375 g
Answer:
9.375 g of strontium -90 will remain after 116 years.
Use Order of Operations!! Remember PEMDAS!
P: Parentheses first
E: Exponents (ie Powers and Square Roots, etc.)
MD: Multiplication and Division (left-to-right)
AS: Addition and Subtraction (left-to-right)
7+25•4 (multiply 25 by 4 first)
7+100 (then add 7 to 100)
107
So your final answer would be 107
Hope this helped and I hope you have an awesome day!! :D
These are the important equations:
(1) q = 0.4x0.6y
(2) r = 26000x + 365y (r is the annual operating costs)
Since q is given (q=1000), we can express y in terms of x:
1000 = 0.4x0.6y
y = 1000/[(0.4x)(0.6)]
y = 12500/3x ----> we substitute this to equation 2
r = 26000x + 365(12500/3x)
r = 26000x + 1520833.33x^-1
r should be minimized. In calculus, we differentiate this and equate to zero. Then we can determine x, which is the number of employees.
dr/dx = 26000x - 1520833.33x^-2 = 0
1520833.33/x^2 = 26000
26000x^2 = 1520833.33
x^2 = 58.4935
x = 7.6
x=8
Thus, you should employ 8 employees to produce 1,000 automobiles a year with a minimum annual operating cost.