Cacl2 dissolve in water according to the following equation
Cacl2 + H2O = Ca(OH) + Hcl
Volume= moles/molarity
The reacting ratio between CaCl2 to Ca(OH) is 1:1
therefore moles of solution is also 0.0262 moles hence volume is =
0.0262mol/ 0.52mol/l = 0.0504L or50.4ml
Physical change. you are physically altering it, not chemically
Answer:
-2? if wrong im sorry please tell me what I did that was incorrect ty Explanation:
How about putting one battery in the freezer while putting another by a radiator or something that gives off heat. Leave them for an hour, then place them in an object that uses batteries and time how long it takes for it to die: Note: It may take many hours for the battery to fully deplete.
Answer:
283.725 kJ ⋅ mol − 1
Explanation:
C(s) + 2Br2(g) ⇒ CBr4(g) , Δ H ∘ = 29.4 kJ ⋅ mol − 1
Br2(g) ⇒ Br(g) , Δ H ∘ = 111.9 kJ ⋅ mol − 1
C(s) ⇒ C(g) , Δ H ∘ = 716.7 kJ ⋅ mol − 1
4*eqn(2) + eqn(3) ⇒ 2Br2(g) + C(s) ⇒ 4 Br(g) + C(g) , Δ H ∘ = 1164.3 kJ ⋅ mol − 1
eqn(1) - eqn(4) ⇒ 4 Br(g) + C(g) ⇒ CBr4(g) , Δ H ∘ = -1134.9 kJ ⋅ mol − 1
so,
average bond enthalpy is 
= 283.725 kJ ⋅ mol − 1
