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solmaris [256]
2 years ago
14

How many moles of CaCl₂ are required to produce 45.97 grams of NaCl?

Chemistry
1 answer:
marin [14]2 years ago
6 0
Answer is 0.7866187543

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A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol
LekaFEV [45]

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

\rho_t=1025000 gmL^{-1}

6 0
3 years ago
What is the mass of H2O in 3 moles?
lions [1.4K]

La respuestas de lo que descirbiste es 18.02 gramos

Saludos


7 0
3 years ago
What is the density of a liquid if the volume is 25 mL and the mass is 20.0 g?
LenKa [72]

Answers:  

                   Density = 0.8 g/mol.        

Given data:

                   v = 25 ml

                    m = 20 g

                    δ = ?

Solution:

               Formula for calculating density is given as,

                Density = Mass / Volume    

                 putting values  

                 Density = 20.0 g / 25 ml

                  Density = 0.8 g/mol.

3 0
3 years ago
Explain the steps for naming an oxy-acid (refernce pg. 252)
nata0808 [166]

Answer:

The first element is always named first, using entire element name.

Second element is named using its root and adding the suffix -ide.

Prefixes are used to indicate the number of atoms of each element that are present in the compound.

Explanation:

8 0
3 years ago
A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specif
vekshin1

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (t_{1}) = 25°C

final temperature (t_{2}) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = \frac{1097}{15.75 * (177-25)}

c = 0.45 J/kg°C

<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>

8 0
3 years ago
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