Someone better come get her because she dancing like a s.t.i.p.p.e.r
All the correct answers of the equations using order of operations are;
B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3
C. 48 ÷ 8 + 2³ = 5 + 3²
<h3>How to use order of operations?</h3>
The rule used for order of operations is PEMDAS and it states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.
Using the PEMDAS rule, the solutions would be as follows:
A. 9² − 7² = 20 ÷ (7 − 2)
81 - 49 = 20 ÷ 5
32 = 4
Thus, this is not true.
B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3
56 ÷ 2 − 12 = 22 - 6
28 - 12 = 16
16 = 16
Thus, this is true.
C. 48 ÷ 8 + 2³ = 5 + 3²
6 + 2³ = 5 + 9
6 + 8 = 14
14 = 14
Thus, this is true.
D. 150 ÷ 5² = 30 − 4² − 12
150 ÷ 25 = 30 − 16 − 12
6 = 30 - 28
6 = 2
Thus, this is not true.
Read more about Order of operations at; brainly.com/question/550188
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Complete question is;
Which equations are true equations? Select all correct answers.
A. 9² − 7² = 20 ÷ (7 − 2)
B. 8⋅7 ÷ 2 − 12 = 22 − 2⋅3
C. 48 ÷ 8 + 2³ = 5 + 3²
D. 150 ÷ 5² = 30 − 4² − 12
In order to find the area for a strange shape, you divide it up into simpler figures. In this case, you already know that it can be divided into 4 triangles, so find the area of each triangle and add them up. Hope this helped!
This problem is represented in the Figure below. So, we can find the components of each vector as follows:


Therefore:

So:

Finally, the magnitude is:
