Answer:
Step-by-step explanation:
Consecutive numbers: 1, 2, 3, 4, 5.
As we can see it's the latest plus 1
So,
x, x + 1, x + 1 + 1, x + 1 + 1 + 1
x, x + 1, x + 2, x + 3 and so on
So it's x + 1.
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:
*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
12 People would be able to have 1 half kilogram of chocolate.
In order to solve this problem you have to multiply 6 by 2. There are two halves in a whole. 6 times 2 is equal to 12.