The correct answer to the question is : 4000 N
EXPLANATION:
As per the question, the mass of the roller coaster is given as m = 2000 kg
The acceleration of the roller coaster is given as a = 2m/s2
We are asked to calculate the net force acting on the roller coaster.
From Newton's second laws of motion,we know that net external force acting on a particle is equal to the product of mass with acceleration of the particle.
Mathematically it is written as-
F = ma
Hence,net force acting on the roller coaster is calculated as-
F = 2000Kg×2m/s2
= 4000 N.
Here, Newton (N) is the unit of force.
Hence,net force acting on the roller coaster is 4000 N.
<h2>Answer:</h2>
The speed of atoms depends upon:
- Temperature: Speed of atom is directly proportional to the temperature of atoms.
- Pressure : It is also directly proportional to the speed of an atom.
- Volume of gas : As the volume of gas increases, collision between atoms increases with increasing the speed of atom
- Number of atoms surrounding: More number of atoms leads to more collisions, increasing speed of atoms.
Answer:
39.40 MeV
Explanation:
<u>Determine the minimum possible Kinetic energy </u>
width of region = 5 fm
From Heisenberg's uncertainty relation below
ΔxΔp ≥ h/2 , where : 2Δx = 5fm , Δpc = hc/2Δx = 39.4 MeV
when we apply this values using the relativistic energy-momentum relation
E^2 = ( mc^2)^2 + ( pc )^2 = 39.4 MeV ( right answer ) because the energy grows quadratically in nonrelativistic approximation,
Also in a nuclear confinement ( E, P >> mc )
while The large value will portray a Non-relativistic limit as calculated below
K = h^2 / 2ma^2 = 1.52 GeV
Answer: the contents of this container weighs 4905 kg.m/s²
Explanation:
Given that;
volume of a container V = 0.5 m³
we know that standard gravitational acceleration g = 9.81 m/s²
specific volume of liquid filled in the container v = 0.001 m³/kg
now we express the equation for weight of the container.
W = mg
W = (pV)g
W = Vg / ν
so we substitute
W = (0.5 m³)(9.81 m/s ) / 0.001 m³/kg
W = 4.905 / 0.001
W = 4905 kg.m/s²
Therefore, the contents of this container weighs 4905 kg.m/s²
I believe the answer is C- payload