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Nina [5.8K]
3 years ago
5

How do scientists estimate how old the universe is?

Physics
1 answer:
svet-max [94.6K]3 years ago
8 0
13.772 billions years old
I hope this did help.
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Why do you see lightning before you hear thunder
igomit [66]

Answer: When a lightning bolt travels from the cloud to the ground it actually opens up a little hole in the air, called a channel. Once then light is gone the air collapses back in and creates a sound wave that we hear as thunder. The reason we see lightning before we hear thunder is because light travels faster than sound!

Explanation:

5 0
3 years ago
A skydiver of mass 113kg
yan [13]

Answer:

Option b.

Explanation:

Weight of skydiver = mass × acceleration due to gravity

= 113 × 9.81 N

= 1108.53 N

Now,

The weight is acting downwards and air resistance is acting upwards. So,

Net force = weight - air resistance

Net force = 1108.53 - 660

Net force = 448.53

Closest value is option b.

4 0
3 years ago
A roller coaster car is going over the top of a 18-mm-radius circular rise. At the top of the hill, the passengers "feel light,"
Andre45 [30]

Answer:

0.29713 m/s

Explanation:

m = Mass of person

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity

r = Radius = 18 mm

By balancing the forces in the system we have

mg-N=\dfrac{mv^2}{r}\\\Rightarrow mg-\dfrac{mg}{2}=\dfrac{mv^2}{r}\\\Rightarrow v=\sqrt{r(g-\dfrac{g}{2})}\\\Rightarrow v=\sqrt{0.018\times (9.81-\dfrac{9.81}{2})}\\\Rightarrow v=0.29713\ m/s

The velocity of the coaster is 0.29713 m/s

7 0
3 years ago
A car has a mass of 1,000 kilograms. The weight of the car is blank newtons. Use g = 9.8 N/kg for gravity.
Komok [63]
The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
So the car has a weight of 9800 N.
3 0
3 years ago
How does the work required to stretch a spring 2 cm compare with the work required to stretch it 1 cm
LuckyWell [14K]

Answer:

The work done required is W_{1}=4W_{2}

Explanation:

Given that,

Stretch spring = 2 cm

Stretch spring = 1 cm

We need to calculate the work done

Using formula of work done

W_{1}=\dfrac{1}{2}kx_{1}^2

Put the value into the formula

W_{1}=\dfrac{1}{2}\timesk\times0.02^2.....(I)

We need to calculate the work done

Using formula of work done

W_{2}=\dfrac{1}{2}kx_{2}^2

Put the value into the formula

W_{1}=\dfrac{1}{2}\timesk\times0.01^2.....(II)

We need to calculate the work done

Using equation (I) and (II)

\dfrac{W_{1}}{W_{2}}=\dfrac{\dfrac{1}{2}\timesk\times0.02^2}{\dfrac{1}{2}\timesk\times0.01^2}

\dfrac{W_{1}}{W_{2}}=\dfrac{0.02^2}{0.01^2}

W_{1}=4W_{2}

Hence, The work done required is W_{1}=4W_{2}

3 0
4 years ago
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