Answer:
θ = 25.4º
Explanation:
For this exercise we can use the projectile launch equations, let's use the scope ratio
R = vo² sin 2θ / g
For the first ball
R1 = 35² 2 sin (2 30) /9.8
R1 = 108.25 m
For the second ball, they ask that the second ball fall in the same place, so the horizontal distance is the same
R2 = R1
Therefore we calculate the angle
sin 2θ = R1 g / vo²
sin 2θ = 108.25 9.8 / 37²
sin 2θ = 0.7749
2θ = sin⁻¹ (0.7749)
2θ = 50.8º
θ = 25.4º
Answer:
1. and 2. If the buoyant force is greater than the object's weight, the object rises to the surface and floats. If the buoyant force is less than the object's weight, the object sinks. If the buoyant force equals the object's weight, the object can remain suspended at its present depth.
3. When the buoyant force equals one ton, it will sink no further. When any boat displaces a weight of water equal to its own weight, it floats. This is often called the “principle of flotation” where a floating object displaces a weight of fluid equal to its own weight.
Explanation:
Can anyone help me with my history question.
If one tree bumps into another tree, it's entirely possible
that a car could get away without a scratch.
Answer:
first number is 113 and the second number is 15
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