A single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm and a screen is placed a certain distance behind the slit so that the central bright band of the diffraction pattern is 18 mm wide then the width of slit is 1.667 mm .
<h3>How is the width calculated?</h3>
Given ,
λ = 600 × 10⁻⁹
D = 50
d = 18 mm
The position of central maxima in the diffraction pattern is
w = Dλ / d
∴ w = (50 × 600 × 10⁻⁹ ) / (18 × 10⁻³ )
∴ w = 30000 × 10⁻⁹ / 18 × 10⁻³
∴ w = 30 × 10⁻⁶ / 18 × 10⁻³
∴ w = 1.667 × 10⁻³
∴ w = 1.667 mm
Hence, the width of the central bright fringe of the diffraction pattern will be 1.667 mm.
<h3>
What is the central bright band of diffraction?</h3>
- The width of the central diffraction peak is found to be inversely proportional to the slit width.
- Increasing the width magnitude a decreases the angle θ at which the intensity first goes to zero, narrowing the central band.
- Reducing the width of the slit also increases the angle θ and widens the central band.
- The width and spacing of the bright bands on the screen behind the slit depend on the distance between the slit and the screen.
- Therefore, the light intensity distribution becomes diffracted light.
Can learn more about the slit experiment from brainly.com/question/14703580
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