TRUE............................
Answer:
<h2>A. 4t² - 32t + 64</h2>
Step-by-step explanation:
Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:
f(t - 3) = 4(t - 3)² - 8(t - 3) + 4
<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>
f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4
f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4
f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28
f(t - 3) = 4t² - 24t + 36 - 8t + 28
f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)
f(t - 3) = 4t² - 32t + 64
Answer:
option a
Step-by-step explanation:
2 lines are said to be parallel when they don't intersect each other & they won't meet each other if the distance ( which separates both the lines intersecting each other ) is perpendicular to both the lines.
Here in the figure AC is perpendicular to both AB & CD. Hence AB || CD. Taking BC as transversal , m(2) = m(4) = 35°
Answer is: B
Step-by-step explanation: correct answer is B
b
2
−a
2
Given, acotθ+bcscθ=p
bcotθ+acscθ=q
⇒p
2
−q
2
=(p−q)(p+q)
=[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]
=[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]
=(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)
=(a
2
−b
2
)(cot
2
θ−csc
2
θ)
=(−1)(a
2
−b
2
)[∵csc
2
θ−cot
2
θ=1]
=(b
2
−a
2
)
Answer:
I believe it's A, but I may be wrong. I am sorry if I'm wrong.
