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olga2289 [7]
3 years ago
13

An object accelerates from rest to a velocity of 34 m/s

Physics
1 answer:
Korolek [52]3 years ago
8 0

Answer:

6.8m/s²

Explanation:

Given parameters:

Initial velocity = 0m/s

Final velocity  = 34m/s

Distance  = 70m

Unknown:

To solve this problem we apply one of the motion equations;

     V²   = U² + 2aS

where V is the final velocity

           U is the initial velocity

           a is the acceleration

         S is the distance covered

Input the parameters and solve;

   34² = 0² + 2 x a x 70

  34² = 140a

   a  = 6.8m/s²

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bagirrra123 [75]

Answer:

 θ =  21.8º

Explanation:

We can solve this exercise using Newton's conditions for equilibrium, in the attached we can see a diagram of the forces.

The most used coordinate system is an axis parallel to the plane (x axis) and an axis perpendicular to the plane (y axis), let's write Newton's equations on this axes

Y Axis

       N- W_{y} = 0

       N = W_{y}

X axis

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Let's use trigonometry to find the normal ones

     sin θ = Wₓ / W

     cos θ = W_{y} / W

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The friction force has the formula

     fr = μ N

     fr = μ (W cos θ)

We substitute in 1

    μ mg cosθ = mg sin θ

    μ cos θ = sin θ  

    tan θ = μ

   θ = tan⁻¹ μ

calculate

     θ = tan⁻¹ 0.40

     θ =  21.8º

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Answer:

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Explanation:

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Explanation:

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