The equation for centripetal acceleration is Ac= v^2/r.
Ac: centripetal acceleration
v: velocity
r: radius
C. Frequency is a measure of how many waves pass by in one second.
Answer: The mass is 3.58*10^-2 g
Explanation: In order to calculate the mass corresponding to of a small spherical shot of copper inside a graduate cylinder with water we have considered the total volume of water incresed after put the cooper pieces.
In this sense the total increased volume of water is equal to the volume of the 125 small spherical shot of copper so we have the following:
0.5 mL= 125* volume of each piece of cooper=125*Vcopper
Vcooper=0.5/125 mL=5*10^-7 m^3/125=4*10^-9 m^3
Therefore the mass corresponding to each copper piece is equal to:
density of copper* Vcopper piece= 8960 Kg/m^3*4*10^-9 m^3=3.58*10^-5 Kg = 3.58*10^-2 g
<span>You can use the equation
V_xf = V_xi + a_x(t)
V_xf = 20.0m/s
V_xi = 0m/s
ax = 2.0
t
Thus, solve for t and get 10seconds
and then take 5 seconds to break after 20 seconds of driving
so for
a) 10 + 20 + 5 = 35 seconds
</span><span>for part b)
You can use the formula
Delta x/Delta t = average velocity
Need to find xf, knowing xi = 0
Thus, use the formula
x_f = x_i + V_xi(t) + (1/2)a_x(t)^(2)
x_f = 0 + 0(10) + (1/2)(2.0)(10)^(2)
x_f = 100m
so for the first 10 seconds the truck traveled 100ms
At a speed of 20m/s
20m/s = xm/20s
20*20 = x
x = 400
thus we have 100+400 = 500m
then it slows down from 500m to x_f
thus I use the equation
x_f = x_i + (1/2)(V_xf + V_xi)t
x_f = 500 + (1/2)(0 + 20)(5)
x_f = 500 + 50
x_f = 550
therefore the total distance traveled is 550m
</span>
<span>to calculate average velocity
550/35 = 16m/s
thus
V_xavg = 16m/s</span>
Answer:
41.27m/s
Explanation:
According to law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the velocity after impact
Given
m1 = 0.2kg
u1 = 43.7m/s
m2 = 45.9g = 0.0459kg
u2 = 30.7m/s
Required
Velocity after impact v
Substitute the given parameters into the formula
0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v
8.74+1.409 = 0.2459v
10.149 = 0.2459v
v = 10.149/0.2459
v = 41.27m/s
Hence the speed of the golf ball immediately after impact is 41.27m/s