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Klio2033 [76]
4 years ago
12

Andre is studying snails and how fast they travel. He observes three groups of snails containing four snails each. Here are the

recorded observations from Andre’s notebook: Group A Snails averaged a speed of 4.7cm/min in a petri dish. Group B Snails averaged a speed of 2.8 cm/min on sandpaper. Group C Snails averaged a speed of 3.3 cm/min in the dirt. Based on this data, what is affecting the snails’ speed?
Physics
1 answer:
Olin [163]4 years ago
4 0
The material that the snails are moving on affects their speed. On a smooth material, (petri dish) the snails moved the fastest. On a rough material (sandpaper) the snails moved the slowest. On dirt, a compromise between smooth and rough, the snails moved at a medium pace. The material and possibly friction affect this.
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Your town has decided to build a new power plant to replace the old coal burning plant. Suggest a renewable resource that they c
Gelneren [198K]
Hmm...
dam power plant (not sure if this is considered renewable): benefits: as it creates a tourist spot bringing more money and provides electricity. 
disadvantages: restricts flow of water to farms, costs millions to build.
solar power plant: benefits: sunlight just keeps coming, produces a lot of electricity for maybe half the cost.
disadvantages: takes a large crew to maintain, mostly needs to be in an open area.
Wind farm: benefits: wind we don't have to worry about much, just blows through and turns the turbines, and can produce electricity almost 24/7.
disadvantages: unsightly, needs open space and costs a lot to build
Take your pick!

8 0
4 years ago
Read 2 more answers
A 6.20 g bullet moving at 929 m/s strikes a 850 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
nekit [7.7K]

Answer:

(a) Final speed of block = 3.2896 m/s

(b) 6.7350 m/s is the speed of the bullet-block center of mass?

Explanation:

Given that:

Mass of bullet (m₁) = 6.20 g

Initial Speed of bullet (u₁) = 929 m/s

Final speed of bullet (v₁) = 478 m/s

Mass of wooden block (m₂) = 850g

Initial speed of block initial (u₂) = 0  m/s

Final speed of block (v₂) = ?

<u>By the law of conservation of momentum  as:</u>

<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>

6.20×929 + 850×0 = 6.20×478 + 850×v₂

Solving for v₂, we get:

<u>v₂ = 3.2896 m/s</u>

Let the V be the speed of the bullet-block center of mass. So,

V = [m₁* u₁]/[m₁ + m₂]  (p before collision = p after collision)

   = [6.2 *929]/[5.2+850]

<u>V = 6.7350 m/s </u>

7 0
3 years ago
Comic strip hero superman meets an asteroid in outer space and hurls it at 100m/s. he has a mass of "m". The astroid has a mass
Katyanochek1 [597]

Answer:

v = -10⁵ m/s

Explanation:

given,

speed of asteroid,v' = 100 m/s

mass of superman = m

mass of asteroid,M = 1000 m

recoil velocity of superman,v= ?

using conservation of momentum.

m u + M u' = m v + M v'

initial velocity of asteroid and superman is equal to  zero

 0 + 0 = m v + 1000 m x 100

m v = -100000 m

    v = -10⁵ m/s

superman's velocity after throwing the asteroid is equal to v = -10⁵ m/s

8 0
4 years ago
A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
sp2606 [1]

Answer:

A) 10 m/s

Explanation:

We know that according to conservation of momentum,

m1v1 + m2v2 = m1u1 + m2u2  ..............(equation 1)

where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.

From the given data

If truck and car are two bodies

truck :       m1 = 2000 Kg           v1 = 5 m/s                u1 = 0

car    :        m2 = 1000 kg           v2 = 0                      u2 = ?

final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.

substituting the values in equation 1, we get

(2000 x 5) + 0 = 0 + (1000 x u2)

u2 = \frac{2000}{1000} x 5

    = 10 m/s

Hence after collision, car moves at a velocity of 10 m/s

3 0
3 years ago
You have a gold nugget and find its mass to be 25 grams. How much volume does this gold nugget occupy?
Kay [80]

According to the solving, the volume that this gold nugget occupies is 1.29 cm³.

<h3>What is volume?</h3>

Volume is a standard measure of three-dimensional space that is occupied. It is typically mathematically represented using standard or SI-derived units. Volume and the concept of length are connected. It is sometimes referred to as the object's capacity.

d= m/ V

m=  dV

V= m/d

<h3>So according to the given data,</h3>

The mass of the gold nugget is 25 grams.

The density of gold is 19.32 g/cm³.

We know that,

m= Vd

To find out the Volume(V),

V= m/d

V= (25 g)/(19.32 g/cm³)

V= 1.29 cm³.

According to the solving, the volume this gold nugget occupies is 1.29cm³.

To know more about questions of volume visit,

brainly.com/question/1578538

#SPJ1

8 0
1 year ago
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