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WARRIOR [948]
2 years ago
12

The periodic table lists all the elements according to the number of __________ they have! You can’t change __________ without c

hanging the element?
If You Help I'll Give You Points
Physics
1 answer:
raketka [301]2 years ago
5 0

Answer:

protons

atomic number

Note: The same atomic number can be associated with several different values of atomic mass, but an element can have only 1 atomic number,

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The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. W
nordsb [41]
Take note of the reaction formula which is PCl5=Cl2+PCl3.
The Keq = [Cl2] * [PCl3] / [PCl5]=2.24*10^-2.
For the reason that the volume is 1 liter, the concentration of Cl2 will be computed through: <span>(2.24 * 10^-2) * 0.235 / 0.174 </span> = 0.0303 mol/L is the answer.
7 0
3 years ago
Read 2 more answers
A normal mode of a closed system is an oscillation of the system in which all parts oscillate at a single frequency. In general
valentina_108 [34]

Answer:

Explanation:

(A)

The string has set of normal modes and the string is oscillating in one of its modes.

The resonant frequencies of a physical object depend on its material, structure and boundary conditions.

The free motion described by the normal modes take place at the fixed frequencies and these frequencies is called resonant frequencies.

Given below are the incorrect options about the wave in the string.

• The wave is travelling in the +x direction

• The wave is travelling in the -x direction

• The wave will satisfy the given boundary conditions for any arbitrary wavelength \lambda_i

• The wave does not satisfy the boundary conditions y_i(0;t)=0&#10;

Here, the string of length L held fixed at both ends, located at x=0 and x=L

The key constraint with normal modes is that there are two spatial boundary conditions,y(0,1)=0&#10;

and y(L,t)=0

.The spring is fixed at its two ends.

The correct options about the wave in the string is

• The wavelength \lambda_i  can have only certain specific values if the boundary conditions are to be satisfied.

(B)

The key factors producing the normal mode is that there are two spatial boundary conditions, y_i(0;t)=0 and y_i(L;t)=0, that are satisfied only for particular value of \lambda_i  .

Given below are the incorrect options about the wave in the string.

•  A_i must be chosen so that the wave fits exactly o the string.

• Any one of  A_i or \lambda_i  or f_i  can be chosen to make the solution a normal mode.

Hence, the correct option is that the system can resonate at only certain resonance frequencies f_i and the wavelength \lambda_i  must be such that y_i(0;t) = y_i(L;t)=0&#10;

(C)

Expression for the wavelength of the various normal modes for a string is,

\lambda_n=\frac{2L}{n} (1)

When n=1 , this is the longest wavelength mode.

Substitute 1 for n in equation (1).

\lambda_n=\frac{2L}{1}\\\\2L

When n=2 , this is the second longest wavelength mode.

Substitute 2 for n in equation (1).

\lambda_n=\frac{2L}{2}\\\\L

When n=3, this is the third longest wavelength mode.

Substitute 3 for n in equation (1).

\lambda_n=\frac{2L}{3}

Therefore, the three longest wavelengths are 2L,L and \frac{2L}{3}.

(D)

Expression for the frequency of the various normal modes for a string is,

f_n=\frac{v}{\lambda_n}

For the case of frequency of the i^{th} normal mode the above equation becomes.

f_i=\frac{v}{\lambda_i}

Here, f_i is the frequency of the i^{th} normal mode, v is wave speed, and \lambda_i is the wavelength of i^{th} normal mode.

Therefore, the frequency of i^{th} normal mode is  f_i=\frac{v}{\lambda_i}

.

6 0
3 years ago
The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists obs
anygoal [31]

Answer:

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

v = 4 m/s

Now the centripetal acceleration of the sea lion is given as

a_c = \frac{v^2}{R}

a_c = \frac{4^2}{0.37}

a_c = 43.2 m/s^2

as we know that

g = 9.8 m/s^2

so we have

a = 4.41 g

Now Percentage of this acceleration wrt maximum jet acceleration is given as

P = \frac{4.41 g}{9g} \times 100

P = 49%

6 0
3 years ago
In Newton’s second law, if the net force acting on object doubles. The object’s Will also double
Anna71 [15]

Answer: Explanation:

If the net force on an object is doubled, its acceleration will double If the mass of an object is doubled, the acceleration will be halved .

3 0
3 years ago
8. How is the crystal size different for extrusive and intrusive igneous rocks?
eduard
<span>Igneous rocks which form by the crystallization of magma at a depth within the Earth are called intrusive rocks. Intrusive rocks are characterized by large crystal sizes, i.e., their visual appearance shows individual crystals interlocked together to form the rock mass.  hope that helped</span>
7 0
3 years ago
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