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3 years ago

HClO4+P4O10=H3PO4+Cl2O7 how do you balance this?

Chemistry

1 answer:

Tom [10]3 years ago

5 0

12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇

<h3>Explanation</h3>

Balance by the conservation of atoms.

Assign coefficient 1 to the species with the largest number of elements and atoms. H₃PO₄ contains three elements. Each of its molecule contains eight atoms, that's two more than the six atoms in a HClO₄ molecule. Start by assigning H₃PO₄ a coefficient of 1.

? HClO₄ + ? P₄O₁₀ → 1 H₃PO₄ + ? Cl₂O₇

There are now three H atoms, one P atom on the product side. H₃PO₄ is the only product that contains H and P atoms. As a result, there should be the same number of H and P atoms on the reactant side.

Among all reactants, only HClO₄ contains H atoms. Each HClO₄ molecule contains one H atom. Three H atoms correspond to three HClO₄ molecule.
Among all reactants, only P₄O₁₀ contains P atoms. Each P₄O₁₀ molecule contains four P atoms. One P atom corresponds to 1/4 of a P₄O₁₀ molecule.

Thus

3 HClO₄ + 1/4 P₄O₁₀ → 1 H₃PO₄ + ? Cl₂O₇

There are three Cl atoms in three HClO₄ molecules. HClO₄ is the only species that contains Cl among all reactants. There are three Cl atoms on the reactant side and shall be the same number of Cl atoms on the product side.

Cl₂O₇ is the only molecule that contains Cl among the products. Each Cl₂O₇ molecule contains two Cl atoms. Three Cl atoms will correspond to 3/2 Cl₂O₇ molecules.

3 HClO₄ + 1/4 P₄O₁₀ → 1 H₃PO₄ + 3/2 Cl₂O₇

Multiply both sides by the least common multiple of the denominators to eliminate the fraction. The least common multiple in this case is four.

12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇

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Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

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Let's multiply the given moles by the molar mass:

$3.35mol(\frac{550.39g}{1mol})$

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.

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boyakko [2]

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What is Inert Gas?

Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
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