Answer:
24%
Explanation:
From the question, the limiting reactant is H2S.
The reaction equation is;
2H2S + O2 → 2S + 2H2O
Number of moles of H2S reacted = 22g/34 g/mol = 0.647 moles
According to the reaction equation;
2 moles of H2S yields 2 moles of sulphur
0.647 moles of H2S yields 0.647 moles of sulphur
So;
Theoretical yield of sulphur = 0.647 moles * 32 g/mol = 20.7 g
Actual yield = 5 g
% yield = actual yield/theoretical yield * 100
% yield =5 g/20.7 g * 100
% yield = 24%
Hello!
If a sample contains 21.2 g N, how many moles of N does it contain?
0.66 mol
1.51 mol
14.01 mol
297.01 mol
We have the following data:
m (mass) = 21.2 g
MM (Molar mass of Nitrogen) = 14 g / mol
n (number of moles) = ?
Formula:
Solving:
Answer:
1.51 mol
_______________________________
I Hope this helps, greetings ... Dexteright02! =)
Answer:
Explanation:
Seven of these isomers having similar pKa values are as follows
1) CH₃ -CH(CH₃)-CH(NO₂)-CH₃
2 ) CH₃ -(CH₂)-CH(NO₂)-CH₂-CH₃
3 ) CH₃ -CH₂-CH₂-CH₂-CH₂-NO₂
4 ) CH₃ -CH₂-CH₂-CH(NO₂)-CH₃
5 )CH₃ -CH(CH₃)(NO₂)-CH₂-CH₃
6 ) CH₃ -CH(CH₃)-CH₂-CH₂-NO₂
7)CH₃ -CH₂-CH₂-CH(CH₃)-NO₂
CH₃-C(CH₃)₂-NO₂
The last isomer has different PKa value because of tertiary carbon attached to nitro group.
Answer:
10.28 mol
Explanation:
S + 2O = SO2
(atm x L) ÷ (0.0821 x K)
(3.45 x 45.6) ÷ (0.0821 x 373)
=5.13726
Then round it to significant figures
=5.14
5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)
=10.28 mol O
