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3 years ago

How are the three beams on a triple beam balance different

1 answer:

4 0

The three beams on a triple beam balance all are different. Each beam should have a differnet unit of measurement. For example, one beam may count in 100's and the other beam may count in 10's and the last beam may count in 1's.

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g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM sol

ICE Princess25 [194]

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻ (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

4 0

2 years ago

Sort the vocabulary word below. Make sure you have come to live session or watched the 5.03 recording. These words will be impor

Stells [14]

Answer:

Electric Current

This is a flow of electrons (such as the flow of electrons in a wire to light up a lamp).

Insulator

These stop the electricity from flowing (think rubber and glass).

Resistance

This is slowing the flow of electrons (the current) and where some of the electrons' energy gets converted into heat.

Conductor

These allow electricity to flow easily through them (think copper and aluminum).

5 0

2 years ago

identify the kind of chemical catalysis and then identify which of the given amino acids can act as a catalyst for the reaction.

Agata [3.3K]

The kind of chemical catalysis is covalent catalysis and among the given amino acids lysine will act as a catalyst for the reaction.

The generation of iminium ions in the transition state of the reaction confirms that it is a covalent catalysis. lysine is the only amino acid that can catalyze the iminium ion generated in the transition state of the reaction.

So the answer for the type of catalysis is covalent catalysis, and the answer for the type of amino acid among the given amino acids that can catalyze the reaction is lysine.

Complete question: (Reaction is attached as a picture)

You can also learn about chemical catalysis from the following question:

brainly.com/question/13553173

#SPJ4

6 0

11 months ago

The scientific study of the behavior of matter near 0 K is called

pshichka [43]

I think it is called condensated matter

8 0

2 years ago

Read 2 more answers

Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l) The average rate of consumption of Br− is 1.20×10−4 M/s over t

dexar [7]

Answer:

0.720 M/s

Explanation:

Let's consider the following balanced equation.

5Br⁻(aq) + BrO⁻₃(aq) + 6H⁺(aq) → 3 Br₂(aq) + 3H₂O(l)

The molar ratio of Br⁻ to Br₂ is 5:3, that is, when 5 moles of Br⁻ are consumed, 3 moles of Br₂ are produced. If the average rate of consumption of Br⁻ is 1.20 × 10⁻⁴ M/s, the average rate of formation of Br₂ is:

$\frac{1.20molBr^{-}}{L.s} .\frac{3molBr_{2}}{5molBr^{-}} =\frac{0.720molBr_{2}}{L.s}$

3 0

2 years ago