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hammer [34]
3 years ago
5

That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small p

art of the overall problem. As the diagram shows, most of an iceberg is actually out of sight, below the water level. Based on this diagram, what is the most likely density of the iceberg? (Assume a density of 1.03 g/mL for seawate
Chemistry
2 answers:
siniylev [52]3 years ago
6 0

Answer:A

Explanation: This means that its density is slightly less than the density of seawater. An object with a density of 0.23 g/cc will float much higher in the water. An object with a density greater than 1.03 g/cc would sink. Therefore the most likely density of the iceberg is 0.88 g/cc.

vitfil [10]3 years ago
3 0
<span>The density of an iceberg is less than that of water and that is why it floats. It is the same as ice cubes floating on water too. Water is a very unique substance in that it is one of few compounds where cooling it past freezing point decreases its density (study hydrogen bonds). The possible answers are therefore A or C. If the majority of the ice is below the water then it should be clear from common sense that A is the correct answer as it would mostly float on the top with just a little under the surface if the answer were as low as C. See Archimedes Principle for an explanation of how much of the ice floats and how much is underwater.</span>
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If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
Amy is in a car moving quickly toward a stationary siren. Just as Amy moves
sineoko [7]

Answer:

Pitch

Explanation:

5 0
3 years ago
What type of reaction is this?—- Large Compound=Element A+Element B
Sav [38]
This reaction is decomposition. It is the breakdown of a compound into simpler and smaller elements.
6 0
3 years ago
Which of the following shows three elements in order of decreasing electronegativity?
damaskus [11]

Answer:

The correct answer is option D which is the decreasing order of conductivity is Mn, O, Ge.

Explanation:

You can easily answer this if you know the periodic trends. For the property of electrical conductivity, it decreases across a period and decreases also down a group. Thus, the most conductive element must be Mn, while the least conductive one is Ge. So, the answer is: -Mn, O, Ge

7 0
3 years ago
Using the first volume and pressure reading on the table as V1 and P1, solve for the unknown values in the table below. Remember
maw [93]
Hope this helps. I provided step by step in the picture below if you want to see how I got these answers.
A= 1.0L
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8 0
3 years ago
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