Answer:
[H⁺] = 0.000048936M
pH = 4.31
Explanation:
Acetic acid, CH₃COOH, dissociates in water as follows:
CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)
And Ka is defined as:
Ka = 1.76x10⁻⁵ = [H⁺] [CH₃COO⁻] / [CH₃COOH]
<em>Where [] are equilibrium concentrations of the species.</em>
<em />
The 0.000185M of acetic acid will decreases X, and X of [H⁺] and [CH₃COO⁻] will be produced. That means Ka is:
1.76x10⁻⁵ = [X] [X] / [0.000185 - X]
3.256x10⁻⁹ - 1.76x10⁻⁵X = X²
3.256x10⁻⁹ - 1.76x10⁻⁵X - X² = 0
Solving for X:
X = -0.000066M → False solution. There is no negative concentrations.
X = 0.000048936
As [H⁺] = X,
[H⁺] = 0.000048936M
And pH = -log [H⁺]
<h3>pH = 4.31</h3>
Valence electrons in NH2Cl:
=1(5)*2(1)*1(7)
=14
So there are 14 valence electrons in NH2Cl
As each stick represents an valence electron pair.
And there are 14 valence electrons, so there can be 7 valence electron pairs.
And for 7 valence electron pairs, 7 sticks needed.
They are more likely to be covalent as covalent compounds usually tend to be radical on the color spectrum with deep purples and blacks and even earwax colored.
Light and energy is captured by green pigment and chlorophyll molecules.
