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mojhsa [17]
3 years ago
10

if a plot weight (in g) vs. volume (in ml) for a metal gave the equation y= 13.41x and r^2=0.9981 what is the density of the met

al?
Chemistry
2 answers:
Bumek [7]3 years ago
8 0

ANS: density = 13.41 g/ml

Density (d) of a substance is the mass (m) occupied by it in a given volume (v).

Density = mass/volume

i.e. d = m/v

m = (d) v -----(1)

The given equation from the plot of weight vs volume is :

y = 13.41 x ----(2)

Based on equations (1) and (2) we can deduce that the density of the metal is 13.41 g/ml

Phoenix [80]3 years ago
7 0

Answer:

13.41 g/mL is the density of the metal.

Explanation:

y= 13.41\times x

Slope intercept form of line:

y = mx +c

y = y, x= x m = 13.41 and c = 0

y= 13.41x + 0

Where y and x parameter as are the weights in grams and volume in milliliter respectively.

\frac{Mass}{Voluime}=\frac{y}{x}=14.41 g/mL

13.41 g/mL is the density of the metal.

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Water can be formed in the following reaction:
just olya [345]

Answer

12

Explanation

We have a balanced chemical equation from the question that depicts the formation of water.

                                                  2H2+O2-->2H2O,


We can clearly see from the equation that, the formation of 2 moles of water molecules requires the input of 2 moles of hydrogen and 1 mole of Oxygen.

So indirectly, it tells that the moles of water molecules will be double of the moles of Oxygen molecules used in the reaction.

So if we say that 6 moles of oxygen is used and the reaction is going in such a way that hydrogen is not a limiting reactant, then 12 moles of water will be produced.


Hope it help!

8 0
3 years ago
What characteristic frequencies in the infrared spectrum of your sodium borohydride reduction product will you look for to deter
kkurt [141]

Answer:

A)The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

B)Characteristic frequency  present in the infrared spectrum will be at a peak of  3300-3400 cm-1 which will be due to O-H stretch.

C)If the product is wet with water there will be no change in the infrared spectrum

Explanation:

The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

Characteristic frequency  present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.

If the product is wet with water there will be no change in the infrared spectrum

5 0
3 years ago
A team of researchers are working on a project to make a new kind of airplane fuel. During their experiment, there was an explos
tiny-mole [99]
Well for a start, this makes absolutely no sense, "discovered a fuel that burns so hot that it becomes cold." 

<span>And yes, it's not science if the experiment can't be repeated. In fact they should WANT it to be repeated so that you can get credit for discovering something new and then possibly harness this effect to produce useful applications. </span>

<span>For all we know they had a fewer of LN2 in the lab that got shredded by the blast, LN2 could certainly have frozen many things (not metal though, since metal is already solid at room temperature, (except for mercury)), and afterwards would leave no trace.</span>
6 0
3 years ago
Which of these is found in the energy levels of an atom?
Paul [167]

Answer:

Electrons

Explanation:

Because the nucleas is In the middle and the Electrons surround it

3 0
2 years ago
the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another
GenaCL600 [577]

Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}

0.4725 × (W +  35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W  = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

7 0
3 years ago
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