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nadezda [96]
3 years ago
15

In the following reaction, what is the relationship between the rate at which the nitrous oxide is used up, the rate at which th

e oxygen is used, and the rate at which the nitrogen dioxide is produced?2N2O(g)+ 3O2(g) → 4NO2(g)
Chemistry
1 answer:
IgorC [24]3 years ago
3 0

Answer :

The relationship between the rate at which the nitrous oxide is used :

\text{Rate of disappearance of }N_2O=-\frac{1}{2}\frac{d[N_2O]}{dt}

The relationship between the rate at which the oxygen is used :

\text{Rate of disappearance of }O_2=-\frac{1}{3}\frac{d[O_2]}{dt}

The relationship between the rate at which the nitrogen dioxide is used :

\text{Rate of formation of }NO_2=+\frac{1}{4}\frac{d[NO_2]}{dt}

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the expression for rate of reaction.

The balanced chemical equations is:

2N_2O(g)+3O_2(g)\rightarrow 4NO_2(g)

The relationship between the rate at which the nitrous oxide is used :

\text{Rate of disappearance of }N_2O=-\frac{1}{2}\frac{d[N_2O]}{dt}

The relationship between the rate at which the oxygen is used :

\text{Rate of disappearance of }O_2=-\frac{1}{3}\frac{d[O_2]}{dt}

The relationship between the rate at which the nitrogen dioxide is used:

\text{Rate of formation of }NO_2=+\frac{1}{4}\frac{d[NO_2]}{dt}

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Answer:

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A 100 gram glass container contains 200 grams of water and 50.0 grams of ice all at 0°c. a 200 gram piece of lead at 100°c is ad
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0 \; \textdegree{\text{C}}

Explanation:

Assuming that the final (equilibrium) temperature of the system is above the melting point of ice, such that all ice in the container melts in this process thus

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The fact that energy within this system (assuming proper insulation) conserves allows for the construction of an equation about variable t.

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66.74 + 1.047 \cdot t + 0.0837 \cdot t = 0.0255 \cdot (80 - t)

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nataly862011 [7]

Answer: 3.96L

Explanation:

PV = nRT

The way I like to do it, it's I get rid of whatever I do not need.

We have to do an equation for sure to make both sides equal and find our desired result.

The pressure is constant, so it would be constant in both sides, therefore, there is no point in using it.

The R is a constant used in both sides so there is no point on using it either.

We don't need to work with moles in this case, so let's forget about the moles.

Therefore we are left with only V (volume ) and T(Temperature)

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OR

T1/V1 = T2/V2

Both of these would work, we always use whatever makes our calculations easier without complicating our lives with the algebra.

That should remind you of Charles' Law

Transform degrees into kelvins

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