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nadezda [96]
3 years ago
15

In the following reaction, what is the relationship between the rate at which the nitrous oxide is used up, the rate at which th

e oxygen is used, and the rate at which the nitrogen dioxide is produced?2N2O(g)+ 3O2(g) → 4NO2(g)
Chemistry
1 answer:
IgorC [24]3 years ago
3 0

Answer :

The relationship between the rate at which the nitrous oxide is used :

\text{Rate of disappearance of }N_2O=-\frac{1}{2}\frac{d[N_2O]}{dt}

The relationship between the rate at which the oxygen is used :

\text{Rate of disappearance of }O_2=-\frac{1}{3}\frac{d[O_2]}{dt}

The relationship between the rate at which the nitrogen dioxide is used :

\text{Rate of formation of }NO_2=+\frac{1}{4}\frac{d[NO_2]}{dt}

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the expression for rate of reaction.

The balanced chemical equations is:

2N_2O(g)+3O_2(g)\rightarrow 4NO_2(g)

The relationship between the rate at which the nitrous oxide is used :

\text{Rate of disappearance of }N_2O=-\frac{1}{2}\frac{d[N_2O]}{dt}

The relationship between the rate at which the oxygen is used :

\text{Rate of disappearance of }O_2=-\frac{1}{3}\frac{d[O_2]}{dt}

The relationship between the rate at which the nitrogen dioxide is used:

\text{Rate of formation of }NO_2=+\frac{1}{4}\frac{d[NO_2]}{dt}

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Olenka [21]

Answer:The correct answer is option 4.

Explanation:

Arrhenius acids are those compounds which gives H^+ ions when dissolved in their aqueous solution.

HA(aq)\rightarrow H^++A^-

Arrhenius bases are those compounds which gives OH^- ions when dissolved in their aqueous solution.

BOH(aq)\rightarrow OH^-+B^+

HBr \& H_2SO_4 are Arrhenius acids because they form H^+ions in their respective aqueous solution.

HBr(aq)\rightarrow H^++Br^-

H_2SO_4(aq)\rightarrow 2H^++SO_{4}^{2-}

Hence, the correct answer is option 4.

6 0
3 years ago
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Give the formula of each coordination compound. Include square brackets around the coordination complex. Do not include the oxid
rodikova [14]

Answer:

sodium hexachloroplatinate(IV)- Na2[PtCl6]

dibromobis(ethylenediamine)cobalt(III) bromide- [Co(en)2Br2]Br

pentaamminechlorochromium(III) chloride-[Cr(NH3)5Cl]Cl2

Explanation:

The formulas of the various coordination compounds can be written from their names taking cognisance of the metal oxidation state as shown above. The oxidation state of the metal will determine the number of counter ions present in the coordination compound.

The number ligands are shown by subscripts attached to the ligand symbols. Remember that bidentate ligands such as ethylenediamine bonds to the central metal ion via two donors.

4 0
3 years ago
For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl
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Answer: The approximate equilibrium partial pressure of H_2S is 3.92  atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

      2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

On reversing the reaction:

     2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

initial pressure  4.00atm    2.00 atm       0

eqm          (4.00-2x)atm      (2.00-x) atm      2x atm

K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}

K_p'=\frac{1}{K_p}=0.67\times 10^5

2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)

0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}

x=1.96

[H_2S]=2x=2\times 1.96=3.92 atm

Thus approximate equilibrium partial pressure of H_2S is 3.92 atm

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3 years ago
The answer to this problem
ss7ja [257]

Answer is A. 24.5 g O2

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2.Which term best describes the processes that change rocks and mountains on Earth’s surface over time?
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Answer:

B. weathering

or erosion

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2 years ago
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