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-Dominant- [34]
3 years ago
9

When magnesium is ignited in air, the magnesium reacts with oxygen and nitrogen.

Chemistry
2 answers:
vampirchik [111]3 years ago
8 0
51: The only coefficient is in the first one i think and it would be a 3
52: Neon (Ne)
53: Mg has a low nuclear charge so all it's electrons would be lost in the electron shell, making the ion smaller than the atom.
Dmitry [639]3 years ago
8 0

51)

Mg(s) + N₂(g) --> Mg₃N₂(s)

There is one Mg atom on the reactant side and three Mg atoms on the product side. So to balance the number of Mg on both side of the equation a coefficient 3 is placed before Mg on the reactant side. The number of N atoms are two on both side of the reaction. Therefore the balanced chemical equation is,  

2Mg(s) + N₂(g) --> Mg₃N₂(s)

52)

The electron configuration of Mg is 1s²2s²2p⁶3s² or [Ne]3s²

The electron configuration of Mg²⁺ is 1s²2s²2p⁶ or [Ne]

The electron configuration of Ne is 1s²2s²2p⁶

Ne he same electron configuration as a Mg²⁺ ion.

53)

Mg has its valence electron in the 3s shell, but Mg²⁺ has no electron in the 3s shell, the valence electron in Mg²⁺is in the 2p orbital. The size of the 2 shell is smaller than the 3 shell. Hence, Mg²⁺ is smaller than Mg.

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Harlamova29_29 [7]
<h2>Answer:</h2>

390 g KNO₃

<h2>General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3><u>Math</u></h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h2>Explanation:</h2>

<u>Step 1: Define</u>

2.3 × 10²⁴ formula units KNO₃

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

<u>Step 3: Convert</u>

<u />2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} ) = 386.172 g KNO₃

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

386.172 g KNO₃ ≈ 390 g KNO₃

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Sort the following chemicals for their ability to act as an oxidizer. List from strongest to weakest; 1 being strongest, 6 being
spin [16.1K]
Answer : If we list the given chemicals according to their increasing oxidising ability then the order will be like this; 1 being the strongest and 6 being the weakest 
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