Answer:
3/4.8/5 s your answer... that is option H
2l + 2w = p
If you already have perimeter and length, you can use this formula to solve for width.
Answer:
Step-by-step explanation:
1) ABCD is a trapezium. AB ║ CD
∠ADC + ∠DAB = 180° { Co interior angles}
110° + ∠DAB = 180
∠DAB = 180 -110
∠DAB = 70°
2) Sum of all angles of trapezium = 360°
∠A + ∠B + ∠DCB + ∠D = 360
70° + 50° + ∠DCB + 110° = 360
230 + ∠DCB = 360
∠DCB = 360 - 230
∠DCB = 130°
3) For finding the height, use Pythagorean theorem
height² + base² = hypotenuse²
height² + 6² = 10²
height² + 36 =100
height² = 100 - 36
height² = 64
height = √64
height = 8 m
4) a = AB = x m
b = 9 m
h = height = 8 m
Area of trapezium = 120 m²
= 120

x + 9 = 120/4
x + 9 = 30
x = 30 - 9
x = 21 m
AB = 21m
Answer:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
Step-by-step explanation:
Given
The attached piece wise function
Required
The domain
To do this, we simply consider the inequalities that bound the values of x.
The inequalities are:
and 
Combine the first two inequalities:
and 
For the inequality to be true, we must have:

In interval notation, the inequality is:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
You can multiply the number of laps each person ran by the yards in each lap and then add them together:
440 + 2(440) + 3(440) + 4(440)
= 440 + 880 + 1,320 + 1,760
= 4,440 yards
Or you can add the laps first, then multiply by the yards in each lap
(1 + 2 + 3 + 4)(440)
= 10 x 440
= 4,400 yards