The temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
Temperature can be represented on a vertical number line with 0 representing 0°F.
Temperatures above 0°F will be located above 0, while temperatures below 0°F will be located below 0.
Given the following temperatures: <em>-3.5℉
, 5℉, 1.5℉, -0.5℉, -2℉, 2.5℉ and -4℉</em>
Therefore, the temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
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Answer:
Mean qualifying speed
= 224.5669mi/hr
Speed that passed the average/mean
= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr
Step-by-step explanation:
Let's understand what mean is then understand what mean qualifying speed is.
First mean is like the average of the seven speed listed below.
So let's find the mean.
Mean = (223.684+ 222.929+ 226.240
+224.037 +226.484+ 225.172
+223.422)/7
Mean = 1571.968/7
Mean = 224.5669
So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.
Mean qualifying speed are
=226.240 ,224.037,226.484
, 225.172
Factors: Numbers that can multiply into a certain number.
The factors of 45 are:
1 (x 45)
3 (x 15)
5 (x 9)
9 (x 5)
15 (x 3)
1 (x 45)
Answer:
Step-by-step explanation:
4 and 6
