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3 years ago

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Three friends all have ages that are consecutive integers. The sum of their ages is 180. What is the age of the oldest friend?

1 answer:

Masja [62]3 years ago

5 0

Answer:

61 yeas old

Step-by-step explanation:

180 is dividable by 3 evenly into 60. If you remove 1 from one of the 60's and add it to another 60, the order is now 59,60,61. So the oldest friend is 61 years old

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What is n/2=−7? Thanks!

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N=-14
-7×2 is -14
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3 is 12% of please help asap

Korvikt [17]

Answer:

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Step-by-step explanation:

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Consider the following algorithm.. for. i is in {1, 2, 3, 4} do. beep. for j is in {1, 2, 3} do. beep. for k is in {1, 2, 3, 4}

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3 years ago

PLEASE ANSWER ASAP! SHOW ALL WORK! WILL GIVE BRAINLIEST!

Iteru [2.4K]

1) $x^2=x\cdot x$ , and $x(x+3)=x^2+3x$ . Subtracting this from the numerator gives a remainder of

$(x^2-13x-48)-(x^2+3x)=-16x-48$

$-16x=-16\cdot x$ , and $-16(x+3)=-16x-48$ . Subtracting this from the previous remainder gives a new remainder of

$(-16x-48)-(-16x-48)=0$

This means that

$\dfrac{x^2-13x-48}{x+3}=x-16$

2) $3x^3=3x^2\cdot x$ , and $3x^2(x+2)=3x^3+6x^2$ . Subtracting this from the numerator gives a remainder of

$(3x^3-x^2-7x+6)-(3x^3+6x^2)=-7x^2-7x+6$

$-7x^2=-7x\cdot x$ , and $-7x(x+2)=-7x^2-14x$ . Subtracting this from the previous remainder gives a new remainder of

$(-7x^2-7x+6)-(-7x^2-14x)=7x+6$

$7x=7\cdot x$ , and $7(x+2)=7x+14$ . Subtracting this from the previous remainder gives a new remainder of

$(7x+6)-(7x+14)=-8$

This means that

$\dfrac{3x^3-x^2-7x+6}{x+2}=3x^2-7x+7-\dfrac8{x+2}$

3) $x+2$ will be a factor of $x^3+3x^2-10x-24$ if dividing the latter by $x+2$ leaves a remainder of 0.

$x^3=x^2\cdot x$ , and $x^2(x+2)=x^3+2x^2$ . Subtracting this from the numerator gives a remainder of

$(x^3+3x^2-10x-24)-(x^3+2x^2)=x^2-10x-24$

$x^2=x\cdot x$ , and $x(x+2)=x^2+2x$ . Subtracting this from the previous remainder gives a new remainder of

$(x^2-10x-24)-(x^2+2x)=-12x-24$

$-12x=-12\cdot x$ , and $-12(x+2)=-12x-24$ . Subtracting this from the previous remainder gives a new remainder of

$(-12x-24)-(-12x-24)=0$

and since the remainder is 0, $x+2$ is indeed a factor of $x^3+3x^2-10x-24$ .

5 0

3 years ago

Which ordered pair is a solution of this

natali 33 [55]

Answer:

(- 3, 2 )

Step-by-step explanation:

To determine which ordered pair is a solution, substitute the x and y- coordinates of the given points into the left side of the equation.

If the result is equal to the right side then the pair is a solution.

(2, - 2)

- 6(2) - 7(- 2) = - 12 + 14 = 2 ≠ 4 ← not a solution

(- 2, 2 )

- 6(- 2) - 7(2) = 12 - 14 = - 2 ≠ 4 ← not a solution

(- 3, 2 )

- 6(- 3) - 7(2) = 18 - 14 = 4 = right side ← a solution

(2, - 3 )

- 6(2) - 7(- 3) = - 12 + 21 = 9 ≠ 4 ← not a solution

(- 3,2 ) is a solution of the equation

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