If x2 = 64and y2 = 121, what is the value of x - y
1 answer:
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X^2 + y^2 - x - 2*y = 0
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2
x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4
coordinates of center are (1/2,1) and the radius is √
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2
x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4
coordinates of center are (1/2,1) and the radius is √
Answer:
Option A: is the correct answer.
Step-by-step explanation:
Given that:
Slope of the line =
Let,
m be the slope of the line perpendicular to the line with slope
We know that,
The product of slopes of two perpendicular lines is equals to -1.
Therefore,
Multiplying both sides by
m =
is the slope of the line perpendicular to the line having slope
Hence,
Option A: is the correct answer.