PLEase HELP ASAP!!! DUE TODAY! will mark brainiest
1 answer:
You might be interested in
Answer:
Answers are in bold type
Step-by-step explanation:
f(x) =
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.
The range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57 and increases when 57 > x > ∞
The x - intercepts: = 0
x(x - 114x) = 0
x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept. So, 0^2 - 114(0) = 0
y-intercept is (0, 0)
We need to know the definition of the "combined function" h(x). I'm going to guess--by looking at answers--that the function is 
making it
This function is undefined wherever the denominator is equal to 0 (division by zero is undefined). Factor the denominator.
The two values of x that make the denominator 0 are 3 and -3, otherwise written
.
This function is undefined wherever the denominator is equal to 0 (division by zero is undefined). Factor the denominator.
The two values of x that make the denominator 0 are 3 and -3, otherwise written