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Mrrafil [7]
3 years ago
13

50 PONITS TO RIGHT AWNSERS!!!

Chemistry
2 answers:
Ivan3 years ago
7 0
Distance and period of time is the correct answer

Hope this helps!
emmasim [6.3K]3 years ago
7 0
To determine an object's speed you need to have distance and period of time like with a car to measure how fast it goes you use miles per hour which is distance and period of time
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Suppose that 0.48 g of water at 25 ∘ C condenses on the surface of a 55- g block of aluminum that is initially at 25 ∘ C . If th
mamaluj [8]

Answer:

49^oC

Explanation:

At 25^oC, the heat of vaporization of water is given by:

\Delta H^o_{vap} = 43988 J/mol\cdot \frac{1 mol}{18.016 g} = 2441.6 J/g

The water here condenses and gives off heat given by the product between its mass and the heat of vaporization:

Q_1 = \Delta H^o_{vap} m_w

The block of aluminum absorbs heat given by the product of its specific heat capacity, mass and the change in temperature:

Q_2 = c_{Al}m_{Al}(t_f - t_i)

According to the law of energy conservation, the heat lost is equal to the heat gained:

Q_1 = Q_2 or:

\Delta H^o_{vap} m_w = c_{Al}m_{Al}(t_f - t_i)

Rearrange for the final temperature:

\Delta H^o_{vap} m_w = c_{Al}m_{Al}t_f - c_{Al}m_{Al}t_i

We obtain:

\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i = c_{Al}m_{Al}t_f

Then:

t_f = \frac{\Delta H^o_{vap} m_w + c_{Al}m_{Al}t_i}{c_{Al}m_{Al}} = \frac{2441.6 J/g\cdot 0.48 g + 0.903 \frac{J}{g^oC}\cdot 55 g\cdot 25^oC}{0.903 \frac{J}{g^oC}\cdot 55 g} = 49^oC

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2 years ago
Hello summer roses~<br>help me with these questions ​
Olegator [25]

Answer:

  • The process of "slaking" of lime refers to the use of excess water for hydration. balanced equation: CaO + H₂0 = Ca(OH)₂ + heat released

  • First lets know which oxide is quick lime - CaO, is basic in nature as a result it combines with acidic oxides using heat. For example we are gonna make it react with silicon dioxide which is a very weak acid: CaO + SiO₂ → CaSiO₃

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Which material is the least likely to be recognized as a mixture by looking at it under a microscope?
adelina 88 [10]
I don't know what the options were but a material that is very likely going to be challenging to recognize under a microscope as a mixture is a homogeneous mixture. A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water!
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2) Copper (II) Chloride

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