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Hitman42 [59]
3 years ago
10

The ions Cr3+ and O2- combine to form the ionic chromium oxide. in what proportions do these ions combine to produce a neutral c

ompound?
Chemistry
1 answer:
anygoal [31]3 years ago
4 0
When ions combine to form neutral compounds, their charges are usually crisscrossed to cancel out any net charge. For this example, Cr3+ and O2- have different charges. Applying the crisscross method, the neutral compound is Cr2O3. This proportion balances out a net charge because two Cr3+ gives a +6 charge, and three O2- gives -6 charge. 
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8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is
Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

T^2\propto R^3

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3  

\dfrac{1}{64}=(\dfrac{R}{R'})^3

R'=4\times R

So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.  

4 0
3 years ago
What genotype will appear in box 4?
Pani-rosa [81]
The genotype will be (tt)
Hope this helps!
7 0
2 years ago
Read 2 more answers
5,6-dimethyl-2-heptyne <br><br> Due in 1 hr pls help me
mina [271]

Answer:

Please see the attached pictures.

Explanation:

☆ To ensure that each carbon has 4 bonds, fill the other bonds with Hs.

4 0
2 years ago
The masses of carbon and hydrogen in samples of four pure hydrocarbons are given above. The hydrocarbon in which sample has the
enot [183]

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

8 0
2 years ago
(6 points) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m
Cloud [144]

<u>Answer:</u> The equation to calculate the mass of remaining isotope is [A]=\frac{20}{10^{-0.217t}}

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = \ln 4=1.386yrs

Putting values in above equation, we get:

k=\frac{0.693}{1.386yrs}=0.5yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.5yr^{-1}

t = time taken for decay process

[A_o] = initial amount of the sample = 20 grams

[A] = amount left after decay process =  ? grams

Putting values in above equation, we get:

0.5=\frac{2.303}{t}\log\frac{20}{[A]}

[A]=\frac{20}{10^{-0.217t}}

Hence, the equation to calculate the mass of remaining isotope is [A]=\frac{20}{10^{-0.217t}}

6 0
3 years ago
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