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Law Incorporation [45]
2 years ago
10

It takes 120 mL of 0.15 M of carbonic acid (H2CO3) to neutralize 300 mL of sodium hydroxide (NaOH) for the following balanced ch

emical reaction:
2NaOH + H2CO3 → N2CO3 + 2NaOH

The concentration of the sodium hydroxide _____.
Chemistry
1 answer:
Tju [1.3M]2 years ago
6 0
First of all, you need to convert mL to L; 120mL = 0.12L, 300mL = 0.3L.

n (moles of carbonic acid) = C (concentration) x V (volume)
n = 0.15M (0.15 mol L-1) x 0.12L
n = 0.018 mol

C (conc. of NaOH) = 0.018 mol x 2 moles (because there’s 2x NaOH) = 0.036 mol
C = n / V
C = 0.036 mol / 0.3 L
C = 0.12 mol L-1
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3 years ago
Please Answer ASAP !
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2.0x 10-2M

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Question 4 point
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Answer:

5393.4gH_2O

Explanation:

Hello there!

In this case, for the described chemical reaction, we can write:

CH_4+2O_2\rightarrow CO_2+2H_2O

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