Answer:
X''(2, -5), Y''(3, -3)
Step-by-step explanation:
You know that reflection in the x-axis changes the sign of the y-coordinate. Points that used to be above the axis are now below by the same amount, and vice versa.
Rotation counterclockwise by 270° is the same as clockwise rotation by 90°. That maps the coordinates like this:
(x, y) ⇒ (y, -x)
The two transformations together give you ...
(x, y) ⇒ (x, -y) ⇒ (-y, -x) . . . . . . . . equivalent to reflection across y=-x.
Using this mapping, we have ...
X(5, -2) ⇒ X''(2, -5)
Y(3, -3) ⇒ Y''(3, -3) . . . . . . on the equivalent line of reflection, so invariant
_____
The attachment shows the original segment in red, the reflected segment in purple, and the rotated segment in blue. The equivalent line of reflection is shown as a dashed green line.
Answer:
<em>Most likely time, </em>according to PERT (Program evaluation and review technique).
Step-by-step explanation:
PERT is "a statistical tool used in <em>project management" (Program evaluation and review technique (2020), </em>in Wikipedia), and it is commonly used with CPM <em>(Critical Path Method)</em> to manage projects.
Inside PERT, there are different defined times to accomplished an activity in a project, that is:
- An <em>optimistic time</em> or minimum time required to accomplished an activity, i.e., if everything goes better than normal, the activity is accomplished before expected.
- A <em>pessimistic time, </em>a time quite the opposite to optimistic time.
- A <em>most likely time</em>, or a time required to accomplished an activity if everything goes as expected or normally.
- An <em>expected time</em>, an statistical estimation.
Considering the question, we have that the <em>time</em> when "the first module of the project could be completed":
- "[...] in as few as 15 days" is the <em>optimistic time</em>.
- "[...] or could take as many as 25 days" is the <em>pessimistic time</em>.
- "[...] but most likely will require 20 days" is the <em>most likely time</em>.
As a result, the <em>20-day estimate</em> is called the <em>most likely time</em> in the context of the PERT/CPM techniques.
Answer:
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

(Right tailed test at 5% level)
Mean difference = 0.2
Std error = 
Z statistic = 1.0540
p value = 0.145941
since p >alpha we do not reject H0.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Jus look and the answer above
Answer:
A shopkeeper marks:
$200 * 1.4 = $280
Step-by-step explanation:
With a discount of 25%:
$280 * 0.75 = $210