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horsena [70]
3 years ago
6

Which geometric series results in a sum of -69,905 ?

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

Its B

Step-by-step explanation:

Used photo math and got it right on plato ;)) yw

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1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
You buy a used car for $6500. The monthly cost of owning the car (including insurance, fuel, maintenance, and taxes) averages $3
pashok25 [27]
Y = 350x + 6500

where x = the number of months you own the car and y = the total cost of buying and owning the car.

This is true because each month, it costs 350, so finding the monthly cost would be multiplying 350 by the number of months, or x.  The + 6500 is there because in addition to the monthly cost, the original price was $6500.
4 0
3 years ago
Select the pair of slopes that are the slopes of perpendicular lines.
agasfer [191]
<h3>\frac{3}{4}\ and\ \frac{-4}{3} are the slopes of perpendicular lines</h3>

<em><u>Solution:</u></em>

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

<em><u>Option 1</u></em>

\frac{1}{2}\ and\ 2

Product = \frac{1}{2} \times 2 = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 2</u></em>

\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1

This option satisfies the slopes of perpendicular lines

<em><u>Option 3</u></em>

\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1

Thus, these are not the slopes of perpendicular lines

<em><u>Option 4</u></em>

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0
3 years ago
find the lcm of 308 and 420
Nat2105 [25]

Answer:

4620

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
I need the answers to this guys please help
Anvisha [2.4K]
C. 660 ft
If you multiply 3 by 22, you get 66, and multiply 10 by 66 and get 660.
8 0
3 years ago
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