<h3>
Answer: Approximately 23.0 cm</h3>
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Work Shown:
a = 20.3
b = unknown
c = 30.7
Apply the pythagorean theorem to find b
a^2 + b^2 = c^2
(20.3)^2 + b^2 = (30.7)^2
412.09 + b^2 = 942.49
b^2 = 942.49-412.09
b^2 = 530.4
b = sqrt(530.4)
b = 23.0304146727757 value is approximate
b = 23.0
I rounded to one decimal place because the other values (20.3 and 30.7) were to one decimal place.
<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
Answer:25
Step-by-step explan students ation:
total number of students=1+1+9+8+3+2+1
total number of students=25
5,10,15,20,25,30,35,40,45,50,55,60
6,12,18,24,30,36,42,48,54,60
10,20,30,40,50,60
The answer is 60
Answer:
19
Step-by-step explanation:
1/2*(5+x)*4=48
