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LenaWriter [7]
3 years ago
10

PLZ HELP IM STUCK!!! In this unit we have learned that the primary focus of portraits in the individual's face or expression. In

this talk, Dass says that the primary focus of her portraits is what? Based on this, do you believe that her photos are considered portraits?
Computers and Technology
1 answer:
iogann1982 [59]3 years ago
8 0
The focus of her photos is the skin tones of her subjects rather than their face or expression, so no, they should not be considered portraits.
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To improve readability,______ use text on a dark green background.
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To improve readability, use white text on a dark green background but <span>the darker text on a lighter background was rated more readable than lighter text on dark backgrounds according to survey in every color combination. Example, red text on white background is more readable than white text on red background.</span>


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3 years ago
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A network with 6 bits remaining for the host portion will have how many usable hosts?​
Readme [11.4K]
<span>A network with 6 bits remaining for the host portion will have 62 usable hosts. The netmask is </span><span>255.255.255.192/26, the shorthand is [6-bit] which is equal to the number of addresses as <span>= 62 hosts + 1 bcast + 1 net base</span></span>
6 0
3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Class Participation: "; cin>>classp; </em>

<em> while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; } </em>

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Test: "; cin>>test; </em>

<em> while(test <0 || test > 100){  cout<<"Test: "; cin>>test; } </em>

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Assignment: "; cin>>assgn; </em>

<em> while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; } </em>

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Examination: "; cin>>exam; </em>

<em> while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; } </em>

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Practice Score: "; cin>>prctscore; </em>

<em> while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; } </em>

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

8 0
3 years ago
Convert the following hexadecimal numbers to decimal: (a) FF (b) F0A2 (c) 0F100 (d) 100
Hatshy [7]

Answer:

a) 255

b) 61602

c)

d)

Explanation:

You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>

For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:

a.               F   F

position    1    0

Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

F*16^{0}=15*1=15\\F*16^{1}=15*16=240

Finally, you'll add your results:

240+15=255

FF=255

b.             F  0  A  2

position   3  2  1   0

2*16^{0}=2*1=2\\A*16^{1}=10*16=160\\0*16^{2}=0*256=0\\F*16^{3}=16*4096=61440\\\\2+160+0+61440=61602\\

F0A2=61602

c.             F  1  0  0

position   3  2  1   0

0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\F*16^{3}=16*4096=61440\\0+0+256+61440=61696\\

0F100=61696

d.              1  0  0

position  2  1   0

0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\\\0+0+256=256\\

100=256

I hope you find this information useful! Good luck!

8 0
3 years ago
A hotel salesperson enters sales in a text file. Each line contains the following, separated by semicolons: the name of the clie
timama [110]

Answer:

see explaination

Explanation:

Java code

//Header file section

import java.util.Scanner;

import java.io.*;

//main class

public class SalesTestDemo

{

//main method

public static void main(String[] args) throws IOException

{

String inFile;

String line;

double total = 0;

Scanner scn = new Scanner(System.in);

//Read input file name

System.out.print("Enter input file Name: ");

inFile = scn.nextLine();

FileReader fr = new FileReader(new File(inFile));

BufferedReader br = new BufferedReader(fr);

System.out.println("Name \t\tService_Sold \tAmount \tEvent Date");

System.out.println("=====================================================");

line = br.readLine();

//Each line contains the following, separated by semicolons:

//The name of the client, the service sold

//(such as Dinner, Conference, Lodging, and so on)

while(line != null)

{

String temp[] = line.split(";");

for(int i = 0; i < temp.length; i++)

{

System.out.print(temp[i]+"\t");

if(i == 1)

System.out.print("\t");

}

//Calculate total amount for each service category

total += Double.parseDouble(temp[2]);

System.out.println();

line = br.readLine();

}

//Display total amount

System.out.println("\nTotal amount for each service category: "+total);

}

}

inputSale.txt:

Peter;Dinner;1500;30/03/2016

Bill;Conference;100.00;29/03/2016

Scott;Lodging;1200;29/03/2016

Output:

Enter input file Name: inputSale.txt

Name Service_Sold Amount Event Date

=====================================================

Peter Dinner 1500 30/03/2016

Bill Conference 100.00 29/03/2016

Scott Lodging 1200 29/03/2016

Total amount for each service category: 2800.0

3 0
3 years ago
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