Which type of stress results when two plates push against one another? A. compression B. tension C. force D. shear

A solution has a [OH−] of 1 x 10−12. What is the pOH of this solution? 2 7 10 12

strojnjashka [21]

-log (1×10^-12) is how you calculate the pOH which in this case is 12

7 0

3 years ago

The N2O4−NO2 reversible reaction is found to have the following equilibrium partial pressures at 100∘C. Calculate Kp for the rea

timofeeve [1]

Answer:

$K_{p}$ for the reaction is 18.05

Explanation:

Equilibrium constant in terms of partial pressure ( $K_{p}$ ) for this reaction can be written as-

$K_{p}=\frac{P_{NO_{2}}^{2}}{P_{N_{2}O_{4}}}$

where $P_{NO_{2}}$ and $P_{N_{2}O_{4}}$ are equilibrium partial pressure of $NO_{2}$ and $N_{2}O_{4}$ respectively

Hence $K_{p}=\frac{(0.095)^{2}}{(0.0005)}$ = 18.05

So, $K_{p}$ for the reaction is 18.05

3 0

4 years ago

What is the Molar Mass of methylammonium bromide: Use the Periodic Table and round to the nearest hundredths.

egoroff_w [7]

The molar mass of methylammonium bromide is 111u.

<h3>What is molar mass?</h3>

The molar mass is defined as the mass per unit amount of substance of a given chemical entity.

Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.

Add it all together and put units of grams/mole after the number.

Atomic weight of H is 1u

Atomic weight of N is 14u

Atomic weight of C is 12u

Atomic weight of Br is 79u

Calculating molar mass of $2H_3NCH_3Br$ =2(1 x3+ 14+12+ 1 x 3 +79) = 111u

Hence, the molar mass of methylammonium bromide is 111u.

Learn more about molar mass here:

brainly.com/question/12127540

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8 0

2 years ago

In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is

irga5000 [103]

Answer:
In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is Hydrogen atom of HBr.

Explanation:
In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.

7 0

3 years ago

An exhaled air bubble underwater at 290.

Vinil7 [7]

The answer for the following problem is mentioned below.