Which type of stress results when two plates push against one another? A. compression B. tension C. force D. shear

As the mass of a star increases the lifespan of the star

ira [324]

Answer:

decreases

Explanation:

4 0

2 years ago

Each atom of an element has the following electron configuration. 1s22s22p63s23p64s23d104p65s24d105p5 What is the name of the el

Temka [501]

Answer;

Iodine

Explanation;

Electron configurations are a way of keeping track of the location of the electrons around the nucleus.

Iodine is an element which belongs to the halogen family. The halogen group includes fluorine, chlorine, bromine, astatine, and iodine.

A neutral iodine atom would also have 53 electrons. Its ground state electron configuration would be:

1s22s22p63s23p64s23d104p65s24d105p5

5 0

3 years ago

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Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c

Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO} *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2$

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

$Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%$

Best regards!

8 0

3 years ago

How common is tryptophan in our food, what effect does it have on our body?

dedylja [7]

I can't give you an exact number or anything for how common it is. However, I can say that it is QUITE common in our food.

There's many effects it has to the human body, therefore I'll only list a few.

~social behavior~irritability~mood swings~sleepiness
Also, if tryptophan is used as a drug it can be used to treat depression. Though, it can only help to a certain extent. It varies as well; depending on the person. (Don't quote me on that completely though.)

I hope this helped :)

5 0

3 years ago

A 14.60g sample of an unknown compound, composed only of carbon, hydrogen, and oxygen, produced 28.6g of CO2 and 14.6g of H2O in

o-na [289]

Answer: The empirical formula for the given compound is $C_{2}H_{5}O$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=28.6g$

Mass of $H_2O=14.6g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 28.6 g of carbon dioxide, $\frac{12}{44}\times 28.6=7.8g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 14.6 g of water, $\frac{2}{18}\times 14.6=1.6$ of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (14.60) - (7.8 + 1.6) = 5.2 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{7.8g}{12g/mole}=0.65moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.6g}{1g/mole}=1.6moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{5.2g}{16g/mole}=0.32moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.32 moles.

For Carbon = $\frac{0.65}{0.32}=2.03\approx 2$

For Hydrogen = $\frac{1.6}{0.32}=5$

For Oxygen = $\frac{0.32}{0.32}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 5 : 1

Hence, the empirical formula for the given compound is $C_{2}H_{5}O_{1}=C_{2}H_{5}O$

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3 years ago

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