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yarga [219]
1 year ago
5

Why is there a discrepancy between a heat of reaction ob-tained from calorimetry and one obtained from bond energies?

Chemistry
1 answer:
Eva8 [605]1 year ago
7 0

While bond energies and bond enthalpies can be used to estimate the heat of reaction (enthalpy change of a reaction), H, the heat of neutralization is the heat released when 1 mole of water is generated by the reaction of an acid and a base (reaction).

For the same type of bond, bond enthalpies differ from compound to compound. For instance, the C-H bond enthalpy in methane is nearly identical to that of ethane, butane, etc. When we look up the bond enthalpy for a C-H bond in a table of bond enthalpies, the average number that results may only be accurate to two or three significant figures.

Each compound's enthalpies of production are listed, and those numbers take into account any minor variations in the enthalpies of each bond. Therefore, the result will be more accurate if you utilize formation enthalpies rather than average bond enthalpies to compute a given reaction's enthalpy change.

Learn more about Bond enthalpy here-

brainly.com/question/9998007

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The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens
son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

<u>Given:</u>

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

<u>To determine:</u>

Total mass of NaCl in kg and in tons

<u>Calculation:</u>

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml

Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g

Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24}  g=4.7*10^{22} g

To convert mass from g to Kg:

1000 g = 1 kg

Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg

To convert mass from g to tons:

1 ton = 9.072*10^6 g

Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons

5 0
3 years ago
What is a function of chloroplast​
Viktor [21]

The primary function of chloroplast is to conduct photosynthesis, which is the process plants use to convert light energy into chemical energy that can be released to fuel the organisms' activities.

8 0
3 years ago
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What do you think a force diagram might look like for a hit that causes a concussion? Draw a diagram. Consider only the person’s
zlopas [31]

Answer: I have the same test message me

Explanation: it won’t let me share my answers

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) write the balanced equation for the reaction that occurs when methanol, ch3oh (l), is burned in air. what is the coefficient o
MaRussiya [10]
2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(g)

k(O₂)=3
3 0
3 years ago
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What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t
Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

<u>Step 1:</u> Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

<u>Step 2:</u> The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g)         ΔH°rxn = -6278 kJ

<u>Step 3:</u> Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

<u>Step 4:</u> Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

<u>Step 5:</u> Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0
3 years ago
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