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neonofarm [45]
3 years ago
12

Factor the polynomial completely 24x^2y-6y

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0
Divide by greatest common factor.
Answer simplified should be 6y(4x^2-1)
Rewrite in the form where a^2-b^2

Answer
6y(2x+1)(2x-1)
You might be interested in
10| x – 4| - 3 > 47​
Andrew [12]

Answer:

x < -1    or    x > 9

Step-by-step explanation:

10|x-4|-3>47

Add 3 to both sides.

10|x-4|-3+3>47+3

Simplify.

10|x-4|>50

Divide both sides by 10.

\frac{10|x-4|}{10} >\frac{50}{10}

Simplify.

|x-4|>5

Apply absolute value rule: If |u|>a,a>0 then u < -a or u>a

x-4 or x-4 >5

x-4

Add 4 to both sides.

x-4+4

Simplify.

x

x-4>5

Add 4 to both sides.

x-4+4>5+4

Simplify.

x>9

Combine the intervals.

x or x>9

8 0
3 years ago
All of the following were advantages the North enjoyed over the South EXCEPT
olganol [36]

Your list does not include any advantages
that the North enjoyed over the South.

5 0
3 years ago
COMPLETE THE FOLLOWING EQUATION USING APPROPRIATE SIGN ( +,-,x,÷) IN THE BOXES GIVEN:
VARVARA [1.3K]

Answer:

) +, -

e) x, ÷

g) ÷

Step-by-step explanation:

6 0
2 years ago
3 − m = −2 (m + 6); m = −15 Yes or No
Nimfa-mama [501]

Answer:

3 − m = −2 (m + 6); m = −15    Yes

5 (p + 3) = −35; p = −4            No

8q = 3 (10 + q); q = 6             Yes


Step-by-step explanation:

3 − m = −2 (m + 6)

3 - m = -2m - 12

m = -15

Answer is Yes


5 (p + 3) = −35

5p + 15 = -35

5p = - 50

p = -10

Answer is  No


8q = 3 (10 + q)

8q = 30 + 3q

5q = 30

q = 6

Answer is  Yes

5 0
3 years ago
Find the coordinates of the missing vertex of rectangle ABCD with A(−5, 4), B(2, 4), and C(2, 0).
svlad2 [7]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

6 0
3 years ago
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