Answer:
10 N.m
Explanation:
Force * Perpendicular distance.
= 20 N * 0.5 m
= 10 N.m
Answer:
a) A = 0.603 m
, b) a = 165.8 m / s²
, c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
=
= ½ k x²
Emo = 
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
The person that produces more power is Person A because its power is 50watts.
<h3>Calculation of power</h3>
For person A = Power= ,work done/ time
But work done = force × distance
person A = 100×3/6
= 300/6
= 50watts
For person B = 100×5/20
= 500/20
= 25watts
Therefore, the person that produces more power is Person A because its power is 50watts.
Learn more about power here:
brainly.com/question/1634438
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Answer:
a) 24 J
b) Gravitational Force
c) 45 J
d) 0
e) 6.782m/s
Explanation:
a) m = 3kg
v = 4m/s
h = 1.5m
KE = ?
0.5 * 3 * 16 = 24J
b) Gravitational force
c) F = ma = 3 * 10 = 30N
Work done = Force * distance = 30 * 1.5 = 45J
d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving
e) velocity of ball as it strikes the ground = v
where
v is the velocity as it strikes the ground
u is the initial velocity
a is acceleration
s is the distance
Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it
u = 4m/s
a = 10
s = 1.5
=> 
= 
= 
Answer:
Will increase
Explanation:
The period of an oscillating motion is the time it takes for the system to make one complete oscillation.
The period of a spring-mass system is given by the equation:

where:
k is the spring constant
m is the mass attached to the spring
In this problem:
- The mass of the system is increased
- The spring constant is decreased
We observe that:
- The period of the system is proportional to the square root of the mass: so as the mass increases, the period will increase as well
- The period is inversely proportional to the square root of the spring constant: so as the constant decreases, the period will increase
Therefore, this means that in this case, the period will increase.