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Butoxors [25]
4 years ago
13

If the mass attached to a spring is increased and the spring constant is decreased, does the proof of the oscillating does the m

otions increase, decrease or stay the same
Physics
1 answer:
Fofino [41]4 years ago
7 0

Answer:

Will increase

Explanation:

The period of an oscillating motion is the time it takes for the system to make one complete oscillation.

The period of a spring-mass system is given by the equation:

T=2\pi \sqrt{\frac{m}{k}}

where:

k is the spring constant

m is the mass attached to the spring

In this problem:

- The mass of the system is increased

- The spring constant is decreased

We observe that:

- The period of the system is proportional to the square root of the mass: so as the mass increases, the period will increase as well

- The period is inversely proportional to the square root of the spring constant: so as the constant decreases, the period will increase

Therefore, this means that in this case, the period will increase.

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\alpha =  \frac{\omega_f - \omega_i}{\Delta t}
where
\omega_f is the final angular speed of the object
\omega_i is its initial angular speed
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For the wheel in our problem, \omega_f=11.1 rad/s, \omega_i = 0 and \Delta t=2.99 s, so its angular acceleration is
\alpha= \frac{11.1 rad/s-0}{2.99 s}=3.71 rad/s^2
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3 years ago
Bose-Einstein Condensate can be defined by Group of answer choices slowly vibrating molecules all possibilities listed are corre
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The correct option is;

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3 years ago
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In a race, you run 3000 meters east in 21 minutes. What is your velocity in km/min?
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velocity = distance / time      v= d/t          firstly you change 3000 m into km     distance  D = 3000/1000  = 3 km             secondly   time t = 21 min      using velocity formula v = d/t       = 3 km/21min       =0.142km/min

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3 years ago
The submarine emits a pulse of sound to detect other objects in the sea. The sped of sound in sea water is 1500m/s. An echo is r
r-ruslan [8.4K]

Answer:

d = 375 m

Explanation:

The speed of sound is constant in any medium, therefore we can use the uniform motion relationships

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In this case it indicates that the time since the sound is emitted and received is t = 0.50 s, in this time the sound traveled a round trip distance

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let's calculate

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3 years ago
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