Since this is a right triangle and we have an angle and a side we can solve for any other side by using sohcahtoa. Now lets look at what we know we have the angle 35 degrees and the side adjacent to the angle is 10. we are looking for the side opposite to the angle. so we need a formula that uses opposite and adjacent that is toa, tan(angle)=oppisite/adjacent
now lets plug in tan(35)=x/10
x=10*tan(35)
x=7.002 now round to nearest tenth
x=7.0
See the attached picture:
to the nearest tenth = 9.2
It appears that there are 30 students total (14 Male students and 16 Female Students)
We are interested in selecting a male student, and the probability of that happening is 14/30 which simplifies to 7/15
7/15 becomes 0.4667
Convert 0.4667 to a percentage and you are left with 46.67%
Rounded to the nearest whole percent, you get 47%
Answer: 47%
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola? 
.
At this point you have three parameters to play with, and from the fact that 
we can already fix one of them, in particular 
. At this point I would recommend picking an easy value for one of the two, let's say 
(or even 
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need 
, and at that point the first condition is guaranteed; using the second to find k we get 
Or how about a sine wave that oscillates around 2? with a similar reasoning you get
Sky is the limit.
Answer: A is first
Step-by-step explanation:
