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astraxan [27]
1 year ago
13

(n+8)+(n−12) Please help

Mathematics
1 answer:
Sonbull [250]1 year ago
6 0

Answer:

=n+8+n+−12

=(n+n)+(8+−12)

=2n+−4

Answer:

=2n−4

= 2(n-2)

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The total bill for five people was $74.90. They Agreed to leave a 20% tip and divide the total cost evenly. How much did each of
Bingel [31]
TIP:
74.90*.2=14.98 
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Hope this helps!
3 0
2 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
2 years ago
What is the value of 4x + 9, when x = 4?
Sonbull [250]

Answer:

The answer would be 25.

4x4=16

16+9=25

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

4 0
3 years ago
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Shalnov [3]
16 by Celsius
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2 years ago
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A set of n = 10 pairs of scores has ΣX = 25, ΣY = 30, and ΣXY = 74. What is the value of SP for these data?
Aleksandr-060686 [28]

I think it's B

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2 years ago
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