Answer:
the input for all is add 4
Step-by-step explanation:
The frequency table, stem and leaf plot, and histogram are attached.
The histogram looks similar to the stem and leaf plot, except turned on its side. It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.
The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table. Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.
P=7+7+12+12P=14+24P=38
See the attachment for diagram
Answer:
One of the angles in the triangle might be 50.
AND
The length of the third side must be 11cm or smaller.
Step-by-step explanation:
-The triangle might be an equilateral triangle (having all the same sides and angles). False, since the triangle sum theorem states that all angles inside of a triangle must add up to 180, so an equilateral triangle would need to have all three angles at 60 degrees.
-One of the angles in the triangle must be 120 (false; it can be anything above 90, which is not only 120)
-The length of the third side must be 11cm or smaller. (True, Triangle Inequality Theorem)
-One of the angles in the triangle might be 50 (possibly, so very much true)
The equation formula of the circle is (x-h)^2 + (y-k)^2 = r^2
where (h,k) the point of the center of the circle
and (r) is the radius of the circle
so if the center of the circle = (-2,-4)
by subs. in the formula we get (x-(-2))^2 + (y-(-4))^2 = r^2
then the equation will be (x+2)^2 + (y+4)^2 = r^2
now we want to define the radius of the circle r
since point (3,8) lay on the circle so we can
then subs. in the equation to get the radius
(x+2)^2 +(y+4)^2 = r^2
(3+2)^2 +(8+4)^2 = r^2
25 + 144 = r^2
r^2 = 169
r= 13
the radius of the circle is 13
so by subs in the equation we get
(x+2)^2 + (y+4)^2 = 169
so it is the first answer in the choices